
1. Use the function that comes with JAVA
public static boolean isNumeric(String str){
for (int i = 0; i < str.length(); i++){
System.out.println(str.charAt(i));
if (!Character.isDigit(str.charAt(i))){
return false;
}
}
return true;
}2. Use regular expressions
First, import java.util.regex.Pattern and java.util.regex.Matcher
public boolean isNumeric(String str){
Pattern pattern = Pattern.compile("[0-9]*");
Matcher isNum = pattern.matcher(str);
if( !isNum.matches() ){
return false;
}
return true;
}3. Use org.apache.commons.lang
org.apache.commons.lang.StringUtils;
boolean isNunicodeDigits=StringUtils.isNumeric("aaa123456789");
下面的解释:
isNumeric
public static boolean isNumeric(String str)Checks if the String contains only unicode digits. A decimal point is not a unicode digit and returns false.
null will return false. An empty String ("") will return true.
StringUtils.isNumeric(null) = false
StringUtils.isNumeric("") = true
StringUtils.isNumeric(" ") = false
StringUtils.isNumeric("123") = true
StringUtils.isNumeric("12 3") = false
StringUtils.isNumeric("ab2c") = false
StringUtils.isNumeric("12-3") = false
StringUtils.isNumeric("12.3") = false
Parameters:
str - the String to check, may be null
Returns:
true if only contains digits, and is non-nullAmong the above three methods, the second method is more flexible.
The first and third methods can only verify numbers without the negative sign "-", that is, if you enter a negative number -199, the output result will be false;
The second method is You can check negative numbers by modifying the regular expression. Just change the regular expression to "^-?[0-9]" or "-?[0-9].?[0-9]". Match all numbers.
For more java knowledge, please pay attention to java basic tutorial.
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