Introduction to the method of determining whether it is a triangle in java

Write a method void triangle(int a, int b, int c) to determine whether the three parameters can form a triangle. If it cannot be formed, an exception IllegalArgumentException will be thrown and the exception information will be displayed: a, b, c "Cannot form a triangle"; if it can be formed, the three side lengths of the triangle will be displayed. In the main method, get the three integers input from the command line, call this method, and catch the exception.

a

The sum of the two sides is greater than the third side: a b>c

The difference between the two sides is less than the third side: c-a

import java.util.Arrays;  
import java.util.Scanner;  
  
public class 三角形判断 {  
  
    public static int[] side;  
    public static void main(String[] args) {  
        side=new int[3];  
        Scanner input=new Scanner(System.in);         
        try {  
            side[0]=input.nextInt();  
            side[1]=input.nextInt();  
            side[2]=input.nextInt();  
            Arrays.sort(side);  
            triangle(side[0],side[1],side[2]);  
        } catch (IllegalArgumentException e) {  
            e.getMessage();  
            e.printStackTrace();  
        }catch (Exception e) {  
            e.printStackTrace();  
        }finally {  
            input.close();  
        }  
    }  
      
    public static void triangle(int a,int b,int c)throws Exception{  
        if((a+b>c)&&(a-b<c))  
            System.out.println("可以构成三角形");  
        else  
            throw new IllegalArgumentException("三条边不能构成三角形");  
    }  
  
}

Run results:

For more java knowledge, please pay attention to java basic tutorial.

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