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How to call api interface in python

爱喝马黛茶的安东尼
爱喝马黛茶的安东尼Original
2019-06-13 17:33:5829106browse

How python calls the api interface:

Interface protocol: http, webservice, rpc, etc.

Request method: get, post method

Request parameter format:

a. Get requests are all through url?param=xxx¶m1=xxx

b. Common types of request parameters for post requests include: application/json, application/x-www-form-urlencoded, multipart/form-data, text/html, etc.

You also need to know the url of the interface, parameter type, data format of the returned result, and whether the interface has header, cookie and other information.

Related recommendations: "python video tutorial"

How to call api interface in python

##get method

# coding:utf-8 
import json
from urlparse import parse_qs
from wsgiref.simple_server import make_server  
# 定义函数,参数是函数的两个参数,都是python本身定义的,默认就行了。
def application(environ, start_response):
    # 定义文件请求的类型和当前请求成功的code
    start_response('200 OK', [('Content-Type', 'text/html')])
    # environ是当前请求的所有数据,包括Header和URL,body,这里只涉及到get
    # 获取当前get请求的所有数据,返回是string类型
    params = parse_qs(environ['QUERY_STRING'])
    # 获取get中key为name的值
    name = params.get('name', [''])[0]
    no = params.get('no', [''])[0] 
    # 组成一个数组,数组中只有一个字典
    dic = {'name': name, 'no': no} 
    return [json.dumps(dic)]  
if __name__ == "__main__":
    port = 5088
    httpd = make_server("0.0.0.0", port, application)
    print "serving http on port {0}...".format(str(port))
    httpd.serve_forever()

Request instance

How to call api interface in python

post method

# coding:utf-8 
import json
from wsgiref.simple_server import make_server
# 定义函数,参数是函数的两个参数,都是python本身定义的,默认就行了。
def application(environ, start_response):
    # 定义文件请求的类型和当前请求成功的code
    start_response('200 OK', [('Content-Type', 'application/json')])
    # environ是当前请求的所有数据,包括Header和URL,body
    request_body = environ["wsgi.input"].read(int(environ.get("CONTENT_LENGTH", 0)))
    request_body = json.loads(request_body)
    name = request_body["name"]
    no = request_body["no"]
    # input your method here
    # for instance:
    # 增删改查
    dic = {'myNameIs': name, 'myNoIs': no}
    return [json.dumps(dic)]
if __name__ == "__main__":
    port = 6088
    httpd = make_server("0.0.0.0", port, application)
    print "serving http on port {0}...".format(str(port))
    httpd.serve_forever()

Request instance

How to call api interface in python

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