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If the beginning and end cannot be connected when making carousel images, the effect will be a bit ugly. Here is a method I commonly use:
First explain in text:
If you want to display 5 pictures, respectively 1, 2, 3, 4, 5. Then the introduction of the code is like this: 1, 2, 3, 4, 5, 1
The order of rotation is here Not much to say, the main point is the carousel of 5>1 and 1>5
i represents the index of the current picture
pre represents the button of the previous picture
next represents the button for the next picture
ul represents the picture list
(1) 5>1>2... When the "next" button goes from 5 to 1, it rotates normally in order , when the current picture is the second "1", the next picture should be "2", then when it is "next", the left value of ul is 0, i==1;
(2 ) 1>5>4.... When the "pre" button rotates from the current picture "1" (the first 1) to picture 5, i==4, the left value of ul becomes -5 which is the width of img times, that is, let the first 1 quietly become the last 1;
It’s a bit confusing to express in language, here is the code:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Document</title>
<style type="text/css">
*{padding: 0;margin: 0;}
.container{
width: 273px;height: 163px;overflow: hidden;
position: relative;margin: 0 auto;
}
.list{
position: absolute;width: 1638px;top: 0;left: 0px;
}
.list li{
float: left;list-style: none;
}
.btn{
position: absolute;display: block;width: 40px;height: 50px;font-size: 40px;
text-align: center;font-weight: bold;top: 50%;margin-top: -25px;background-color: rgba(255,255,255,0.5);cursor:pointer;
}
.btn:hover{
background-color: rgba(0,0,0,0.3);color: #fff;
}
.pre{
left: 0;
}
.next{
right: 0;
}
.nav{
position: absolute;bottom: 5px;display: flex;justify-content: center;width: 100%;
}
.nav span{
width: 10px;height: 10px;border-radius: 10px;background-color: #fff;z-index: 2;display: inline-block;margin-right: 10px;cursor: pointer;
}
span.on{
background-color: orange;
}
</style>
</head>
<body>
<div class="container">
<ul class="list" style="left: 0px">
<li><img src="./images/1.png" alt=""></li>
<li><img src="./images/2.png" alt=""></li>
<li><img src="./images/3.png" alt=""></li>
<li><img src="./images/4.png" alt=""></li>
<li><img src="./images/5.png" alt=""></li>
<li><img src="./images/1.png" alt=""></li>
</ul>
<div class="nav">
<span class="on"></span>
<span></span>
<span></span>
<span></span>
<span></span>
</div>
<em class="next btn">></em>
<em class="pre btn"><</em>
</div>
<script type="text/javascript" src="../jquery.js?1.1.11"></script>
<script type="text/javascript">
$(function(){
var i=0;
$('.next').click(function(){
i++;
console.log(i);
moveImg(i);
});
$('.pre').click(function(){
i--;
moveImg(i);
});
$('.nav span').click(function(){
var _index=$(this).index();
i=_index;
moveImg(i);
});
// i的作用：决定下一张图片是谁————也就是说ul的left是多少。
// $('.list').css({left)的值是从图a过度是此时的ul的left。
function moveImg(){
if (i==6) {
i=1;
$('.list').css({'left':'0'});
}
// 是第一张
if(i==-1){
i=4;
$('ul').css({left:(5*-273)});
}
$('.list').stop().animate({'left':-273*i+'px'},1000);
if (i==5) {
$('.nav span').eq(0).addClass('on').siblings().removeClass('on');
}
$('.nav span').eq(i).addClass('on').siblings().removeClass('on');
}
})
</script>
</body>
</html>
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