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How does Java read XML files? Specific implementation

高洛峰
高洛峰Original
2017-01-11 12:36:002466browse

Today’s CSDN FAQ will explain how to read the content of XML files in Java.

Just go to the code, the comments are very clear!

import java.io.*;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
public class XMLReaderTest {
 public static void main(String args[]) {
  Element element = null;
  // 可以使用绝对路劲
  File f = new File("test.xml");
  // documentBuilder为抽象不能直接实例化(将XML文件转换为DOM文件)
  DocumentBuilder db = null;
  DocumentBuilderFactory dbf = null;
  try {
   // 返回documentBuilderFactory对象
   dbf = DocumentBuilderFactory.newInstance();
   // 返回db对象用documentBuilderFatory对象获得返回documentBuildr对象
   db = dbf.newDocumentBuilder();
   // 得到一个DOM并返回给document对象
   Document dt = db.parse(f);
   // 得到一个elment根元素
   element = dt.getDocumentElement();
   // 获得根节点
   System.out.println("根元素:" + element.getNodeName());
   // 获得根元素下的子节点
   NodeList childNodes = element.getChildNodes();
   // 遍历这些子节点
   for (int i = 0; i < childNodes.getLength(); i++) {
    // 获得每个对应位置i的结点
    Node node1 = childNodes.item(i);
    if ("Account".equals(node1.getNodeName())) {
     // 如果节点的名称为"Account",则输出Account元素属性type
     System.out.println("\r\n找到一篇账号. 所属区域: " + node1.getAttributes().getNamedItem("type").getNodeValue() + ". ");
     // 获得<Accounts>下的节点
     NodeList nodeDetail = node1.getChildNodes();
     // 遍历<Accounts>下的节点
     for (int j = 0; j < nodeDetail.getLength(); j++) {
      // 获得<Accounts>元素每一个节点
      Node detail = nodeDetail.item(j);
      if ("code".equals(detail.getNodeName())) // 输出code
       System.out.println("卡号: " + detail.getTextContent());
      else if ("pass".equals(detail.getNodeName())) // 输出pass
       System.out.println("密码: " + detail.getTextContent());
      else if ("name".equals(detail.getNodeName())) // 输出name
       System.out.println("姓名: " + detail.getTextContent());
      else if ("money".equals(detail.getNodeName())) // 输出money
       System.out.println("余额: " + detail.getTextContent());
     }
    }
   }
  }
  catch (Exception e) {
   e.printStackTrace();
  }
 }
}

Then the XML file (test.xml) we test should be placed in the root directory of the project project. Its content is:

<?xml version="1.0" encoding="gbk"?>
<Accounts>
 <Account type="type1">
  <code>100001</code>
  <pass>123</pass>
  <name>李四</name>
  <money>1000000.00</money>
 </Account>
 <Account type="type2">
  <code>100002</code>
  <pass>123</pass>
  <name>张三</name>
  <money>1000.00</money>
 </Account>
</Accounts>

Run the code directly and output:

Root element: Accounts

Found an account number. Area: type1.
Card number: 100001
Password: 123
Name: Li Si
Balance: 1000000.00

Find an account. Area: type2.
Card number: 100002
Password: 123
Name: Zhang San
Balance: 1000.00

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