C++의 일반적인 데이터 구조 문제 및 솔루션

#include <iostream>
#include <stack>

int main() {
    std::stack<int> myStack;
    myStack.push(1);
    myStack.push(2);
    myStack.push(3);

    while (!myStack.empty()) {
        std::cout << myStack.top() << std::endl;
        myStack.pop();
    }

    return 0;
}

#include <iostream>

struct Node {
    int data;
    Node* next;
};

int main() {
    Node* head = new Node;
    Node* second = new Node;
    Node* third = new Node;

    head->data = 1;
    head->next = second;

    second->data = 2;
    second->next = third;

    third->data = 3;
    third->next = nullptr;

    // 遍历链表并打印数据
    Node* current = head;
    while (current != nullptr) {
        std::cout << current->data << std::endl;
        current = current->next;
    }

    // 释放链表内存
    delete head;
    delete second;
    delete third;

    return 0;
}

#include <iostream>

struct TreeNode {
    int data;
    TreeNode* left;
    TreeNode* right;
};

TreeNode* search(TreeNode* root, int value) {
    if (root == nullptr || root->data == value) {
        return root;
    }

    if (value < root->data) {
        return search(root->left, value);
    }

    return search(root->right, value);
}

int main() {
    TreeNode* root = new TreeNode;
    root->data = 4;

    TreeNode* left = new TreeNode;
    left->data = 2;

    TreeNode* right = new TreeNode;
    right->data = 6;

    root->left = left;
    root->right = right;

    // 在二叉树中查找值为2的节点
    TreeNode* result = search(root, 2);
    if (result != nullptr) {
        std::cout << "找到了" << std::endl;
    } else {
        std::cout << "未找到" << std::endl;
    }

    // 释放二叉树内存
    delete root;
    delete left;
    delete right;

    return 0;
}