编写一个C程序,计算存款金额在一些年后的增加利息
计算利息的公式为 −
M=((r/100) * t); A=P*exp(M);
Where r= rate of interest
t=no. of years
P=amount to be deposited
M=temporary variable
A= Final amount after interest
START Step 1: declare double variables Step 2: read amount to be deposited Step 3: read rate of interest Step 4: read years you want to deposit Step 5: Calculate final amount with interest I. M=((r/100) * t); II. A=P*exp(M); Step 6: Print final amount STOP
#include#include #include int main(){ double P,r,t,A,M; printf("amount to be deposit in the bank: "); scanf("%lf",&P); printf(" enter the rate of interest:"); scanf("%lf",&r); printf("
How many years you want to deposit:"); scanf("%lf",&t); M=((r/100) * t); A=P*exp(M); printf("
amount after %0.1lf years with interest is:%0.2lf",t,A); return 0; }
amount to be deposit in the bank: 50000 enter the rate of interest:6.5 How many years you want to deposit:5 amount after 5.0 years with interest is:69201.53
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