C++로 작성되었으며 모든 요소가 X보다 큰 세그먼트 수를 찾습니다.

Input : arr[ ] = { 9, 6, 7, 11, 5, 7, 8, 10, 3}, X = 7
Output : 3
Explanation : { 9 }, { 11 } and { 8, 10 } are the segments greater than 7

Input : arr[ ] = { 9, 6, 12, 2, 11, 14, 8, 14 }, X = 8
Output : 4
Explanation : { 9 }, { 12 }, { 11, 14 } and { 14 } are the segments greater than 8

#include <bits/stdc++.h>
using namespace std;
int main (){
    int a[] = { 9, 6, 12, 2, 11, 14, 8, 14 };
    int n = sizeof (a) / sizeof (a[0]);
    int X = 8;
    int state = 0;
    int count = 0;
    // traverse the array
    for (int i = 0; i < n; i++){
        // checking whether element is greater than X
        if (a[i] > X){
           state = 1;
        }
        else{
           // if flag is true
           if (state)
               count += 1;
            state = 0;
        }
    }
    // checking for the last segment
    if (state)
        count += 1;
    cout << "Number of segments where all elements are greater than X: " << count;
    return 0;
}

Number of segments where all elements are greater than X: 4