처음 n 홀수의 제곱의 합

Input: N = 4
Output: sum =

#include <stdio.h>
int main() {
   int n = 8;
   int sum = 0;
   for (int i = 1; i <= n; i++)
      sum += (2*i - 1) * (2*i - 1);
   printf("The sum of square of first %d odd numbers is %d",n, sum);
   return 0;
}

#include <stdio.h>
int main() {
   int n = 18;
   int sum = ((n*((4*n*n)-1))/3);
   printf("The sum of square of first %d odd numbers is %d",n, sum);
   return 0;
}

The sum of square of first 18 odd numbers is 7770