使用C++编写，找到N叉树中给定节点的兄弟节点数量

#include 
using namespace std;
class Node {  // structure of nodes of our tree.
public:
    int key;
    vector child;
    Node(int data){
        key = data;
    }
};
int main(){
   //     Building The Tree
    Node* Base = new Node(50);
    (Base->child).push_back(new Node(2));
    (Base->child).push_back(new Node(30));
    (Base->child).push_back(new Node(14));
    (Base->child).push_back(new Node(60));
    (Base->child[0]->child).push_back(new Node(15));
    (Base->child[0]->child).push_back(new Node(25));
    (Base->child[0]->child[1]->child).push_back(new Node(70));
    (Base->child[0]->child[1]->child).push_back(new Node(100));
    (Base->child[1]->child).push_back(new Node(6));
    (Base->child[1]->child).push_back(new Node(1));
    (Base->child[2]->child).push_back(new Node(7));
    (Base->child[2]->child[0]->child).push_back(new Node(17));
    (Base->child[2]->child[0]->child).push_back(new Node(99));
    (Base->child[2]->child[0]->child).push_back(new Node(27));
    (Base->child[3]->child).push_back(new Node(16));
    int x = 30;
    queue q;
    q.push(Base);
    bool flag = 0;
    int answer = -1;
    if(Base -> key != x){
        while(!q.empty()){
            auto parent = q.front();
            q.pop();
            for(int i = 0; i < parent -> child.size(); i++){
                if(parent -> child[i] -> key == x){
                    answer = parent -> child.size() - 1;
                    flag = 1;
                    break;
                }
                q.push(parent -> child[i]);
            }
            if(flag)
                break;
        }
        cout << answer << "\n";
    }
    else
        cout << "0\n";
    return 0;
}

3