JavaScript 상속 방법에 대한 자세한 설명(4)

/**
 * @param {String} className
 * @param {String/Function} superClass
 * @param {Function} classImp
 */
function $class(className, superClass, classImp){
    if (superClass === '') superClass = Object;
function clazz() {
        if (typeof this.init == "function") {
            this.init.apply(this, arguments);
        }
    }
    var p = clazz.prototype = new superClass();
    var _super = superClass.prototype;
    window[className] = clazz;
    classImp.apply(p, [_super]);
}

/**
 * 父类 Person
 */
$class('Person','',function(){
this.init = function(name){
this.name = name;
};
this.getName = function(){
return this.name;
};
this.setName = function(name){
this.name = name;
}
});

/**
 * 子类 Man
 */
$class('Man', Person, function(supr){
this.init = function(name, age){
supr.init.apply(this,[name]); // 该句很重要
this.age = age;
};
this.getAge = function(){
return this.age;
};
this.setAge = function(age){
this.age = age;
};
});
var m = new Man('Jack',25);
console.log(m.name); // Jack
console.log(m.age); // 25