오늘 코딩을 하다가 SQL 문제가 발생했습니다.
(추천 관련 mysql 동영상 튜토리얼: "mysql tutorial")
테이블 A의 ID를 테이블 B의 ID와 일치시키려면 테이블 B의 ID 모든 내용 쿼리:
최적화 전:
MySQL [xxuer]> SELECT -> COUNT(*) -> FROM -> t_cmdb_app_version -> WHERE -> id IN (SELECT -> pid -> FROM -> t_cmdb_app_relation UNION SELECT -> rp_id -> FROM -> t_cmdb_app_relation); +----------+ | COUNT(*) | +----------+ | 266 | +----------+ 1 row in set (0.21 sec)
최적화 후:
MySQL [xxuer]> SELECT -> count(*) -> FROM -> t_cmdb_app_version a -> INNER JOIN -> (SELECT -> pid -> FROM -> t_cmdb_app_relation UNION SELECT -> rp_id -> FROM -> t_cmdb_app_relation) b ON a.id = b.pid; +----------+ | count(*) | +----------+ | 266 | +----------+ 1 row in set (0.00 sec)
실행 계획 비교 보기:
MySQL [xxuer]> explain SELECT -> COUNT(*) -> FROM -> t_cmdb_app_version -> WHERE -> id IN (SELECT -> pid -> FROM -> t_cmdb_app_relation UNION SELECT -> rp_id -> FROM -> t_cmdb_app_relation); +----+--------------------+---------------------+-------+---------------+---------+---------+------+------+--------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+--------------------+---------------------+-------+---------------+---------+---------+------+------+--------------------------+ | 1 | PRIMARY | t_cmdb_app_version | index | NULL | PRIMARY | 4 | NULL | 659 | Using where; Using index | | 2 | DEPENDENT SUBQUERY | t_cmdb_app_relation | ALL | NULL | NULL | NULL | NULL | 383 | Using where | | 3 | DEPENDENT UNION | t_cmdb_app_relation | ALL | NULL | NULL | NULL | NULL | 383 | Using where | | NULL | UNION RESULT | <union2,3> | ALL | NULL | NULL | NULL | NULL | NULL | Using temporary | +----+--------------------+---------------------+-------+---------------+---------+---------+------+------+--------------------------+ 4 rows in set (0.00 sec)
MySQL [xxuer]> explain SELECT -> count(*) -> FROM -> t_cmdb_app_version a -> INNER JOIN -> (SELECT -> pid -> FROM -> t_cmdb_app_relation UNION SELECT -> rp_id -> FROM -> t_cmdb_app_relation) b ON a.id = b.pid; +----+--------------+---------------------+--------+---------------+---------+---------+-------+------+--------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+--------------+---------------------+--------+---------------+---------+---------+-------+------+--------------------------+ | 1 | PRIMARY | <derived2> | ALL | NULL | NULL | NULL | NULL | 766 | Using where | | 1 | PRIMARY | a | eq_ref | PRIMARY | PRIMARY | 4 | b.pid | 1 | Using where; Using index | | 2 | DERIVED | t_cmdb_app_relation | ALL | NULL | NULL | NULL | NULL | 383 | NULL | | 3 | UNION | t_cmdb_app_relation | ALL | NULL | NULL | NULL | NULL | 383 | NULL | | NULL | UNION RESULT | <union2,3> | ALL | NULL | NULL | NULL | NULL | NULL | Using temporary | +----+--------------+---------------------+--------+---------------+---------+---------+-------+------+--------------------------+ 5 rows in set (0.00 sec)
위 내용은 IN에서 INNER JOIN으로의 mysql 최적화 공유 예의 상세 내용입니다. 자세한 내용은 PHP 중국어 웹사이트의 기타 관련 기사를 참조하세요!