C# 정규식 일치 및 문자열 함수 바꾸기 예제

string text = @"public string testMatchObj string s string match ";
string pat = @"(\w+)\s+(string)";
// Compile the regular expression.
Regex r = new Regex(pat, RegexOptions.IgnoreCase);
// Match the regular expression pattern against a text string.
Match m = r.Match(text);
int matchCount = 0;
while (m.Success) 
{
 Response.Write("Match"+ (++matchCount) + "<br>");
 for (int i = 1; i <= 2; i++) 
 {
 Group g = m.Groups[i];
 Response.Write("Group"+i+"=&#39;" + g + "&#39;" + "<br>");
 CaptureCollection cc = g.Captures;
 for (int j = 0; j < cc.Count; j++) 
 {
  Capture c = cc[j];
  Response.Write("Capture"+j+"=&#39;" + c + "&#39;, Position="+c.Index + "<br>");
 }
 }
 m = m.NextMatch();
}

Match1
Group1='public'
Capture0='public', Position=0
Group2='string'
Capture0='string', Position=7
Match2
Group1='testMatchObj'
Capture0='testMatchObj', Position=14
Group2='string'
Capture0='string', Position=27
Match3
Group1='s'
Capture0='s', Position=34
Group2='string'

string x = this.txt.Text;
RegexOptions ops = RegexOptions.Multiline;
Regex r = new Regex(@"\[(.+?)\]", ops); //\[(.+?)\/\]  @"\[(.+)\](.*?)\[\/\1\]"
//Response.Write(r.IsMatch(x).ToString()+DateTime.Now.ToString());
if (r.IsMatch(x))
{
    x = r.Replace(x, "<$1>");
    Response.Write(x.ToString() + DateTime.Now.ToString());
    //Console.WriteLine("var x:" + x);//输出：Live for nothing
}
else
{
    Response.Write("false" + DateTime.Now.ToString());
}