클래스 이름이 포함된 문자열에서 C 개체를 만드는 방법은 무엇입니까?

template<typename T> Base * createInstance() { return new T; }

typedef std::map<std::string, Base*(*)()> map_type;

map_type map;
map["DerivedA"] = &amp;createInstance<DerivedA>;
map["DerivedB"] = &amp;createInstance<DerivedB>;

return map[some_string]();

// w base.hpp:
template<typename T> Base * createT() { return new T; }

struct BaseFactory {
    typedef std::map<std::string, Base*(*)()> map_type;

    static Base * createInstance(std::string const&amp; s) {
        map_type::iterator it = getMap()->find(s);
        if(it == getMap()->end())
            return 0;
        return it->second();
    }

protected:
    static map_type * getMap() {
        // nigdy nie usuwane (istnieje do zakończenia programu)
        // ponieważ nie możemy zagwarantować poprawnej kolejności usuwania
        if(!map) { map = new map_type; }
        return map;
    }

private:
    static map_type * map;
};

template<typename T>
struct DerivedRegister : BaseFactory {
    DerivedRegister(std::string const&amp; s) {
        getMap()->insert(std::make_pair(s, &amp;createT<T>));
    }
};

// w derivedb.hpp
class DerivedB {
    ...;
private:
    static DerivedRegister<DerivedB> reg;
};

// w derivedb.cpp:
DerivedRegister<DerivedB> DerivedB::reg("DerivedB");

#define REGISTER_DEC_TYPE(NAME) \
    static DerivedRegister<NAME> reg

#define REGISTER_DEF_TYPE(NAME) \
    DerivedRegister<NAME> NAME::reg(#NAME)

typedef boost::variant<Foo, Bar, Baz> variant_type;
template<typename T> variant_type createInstance() {
    return variant_type(T());
}

typedef std::map<std::string, variant_type (*)()> map_type;