PythonでBaseExceptionステートメントを除くtryを使用するにはどうすればよいですか?

try：
     pass
except BaseException as e ：
    异常处理模块

try:
    test = eval(str(input("请输入一个字符串: ")))
    tests = test + "This is a piece of test code"
except BaseException as e:
    print("出现的错误可能是%s"%e)
print("这是一段测试输出")

try:
    test = str(input("请输入一个字符串: "))
    tests = test + " "+"This is a piece of test code"
    print("输入正确的内容则会执行的代码块：",tests)
except BaseException as e:
    print("出现的错误可能是%s"%e)
print("这是一段测试输出")

test = int(input("请输入一个字符串: "))
tests = test + " "+"This is a piece of test code"
print("这是一段测试输出")

arr = {
    "xiaomi":"123",
    "xiaozhang":"456",
    "xiaodede":"7,8,9"
}
arrs = (1,2,3,4,5)
 
try:
    3 / 0
 
    print(arrs[6])
except IndexError :
    print('导入包失败')
except KeyError :
    print('在字典中找不到指定的键')
except ImportError :
    print("索引时没有找到指定序列")
#兜底捕获错误，BaseException 是所有错误的父类可以说是包含了所有常见的错误
except BaseException as e:
    print(arr["mayuanyuan"])
    print(e)

arr = (1,2,3,4,5)
try:
    int("3.1415926")
    print(add)  # 未定义
    print(arr[6]) #超出索引
 
except (IndexError,NameError,ValueError)as e:
    print(e)

try:
    arr = int(input("请输入一个整数: "))
except BaseException as e:
    print(e)
else:
    arrs = arr + 111
    print(arrs)
print("测试结束")

try:
   4 /0
except BaseException as e:
    print(e)
报错： division by zero

i = 0
while True:
    if i == 3:
        print("输入错误次数过多密码已锁定")
        break
    try:
        Divisor = str(input("请输入一个整数： "))
        # A = Divisor/1
        # B = A+1   #如果输出有误就不会执行加1操作直接跳到 except当中
        # print("结果是：",B)
        mima = 'ma123'
        if Divisor == mima:
            i = i+1
            print("登录成功,输入%s次"%i)
            break
    except:
        i = i+1
        print("密码输入错误请重新输入：")
print("登陆了%s次"%i)

md5 = []
try:
    Divisor = str(input("请输入你的密码： "))
 
except:
    print("密码输入错误")
else:
    for i  in  Divisor:
        if i == 1:
            i = "a"
        else:
            i == 2
            i = "b"
    md5.append(i)
    MD5 = Divisor + md5[0]
 
 
 
print("经过加密后的数据%s"%MD5)