mysql sumを使用する方法は何ですか?

select sum(value) as value from table where user_id = 1 and type = 6 and type_son = 2

select 
 
(select sum(value) from table where type = 6 and type_son = 1) as xj0,
 
(select sum(value) from table where type = 6 and type_son = 2) as xj1,
 
(select sum(value) from table where type = 3 and type_son = 3) as xj2,
 
(select sum(value) from table where type = 4 and type_son = 3) as xj3
 
from table where user_id = 1 limit 0,1

select 
 
sum(IF(type = 6 and type_son = 1,value,NULL)) as xj0,
 
sum(IF(type = 6 and type_son = 2,value,NULL)) as xj1,
 
sum(IF(type = 3 and type_son = 0,value,NULL)) as xj2,
 
sum(IF(type = 4 and type_son = 3,value,NULL)) as xj3
 
from table where user_id = 1
 
 
sum(IF('条件判断'，'求和的字段'，'NULL不计算'))  as  '别名'

$v['alls_bonus'] = AccountingLog::find()
        ->select(["
            sum( IF(type = 6 and type_son = 1,value,NULL) ) as xj0,
            sum( IF(type = 6 and type_son = 4,value,NULL) ) as xj1,
            sum( IF(type = 8 and type_son = 4,value,NULL) ) as xj2, 
            sum( IF(type = 3 and type_son = 1,value,NULL) ) as xj3
        "])
        ->where(['user_id'=>1])
        ->asArray()
        ->one();