Javaのマップはキーに基づいてソートできますか?

import java.util.Map;
import java.util.Set;
import java.util.TreeMap;
 
public class TEST {
 
    public static void main(String[] args) {
        TEST t = new TEST();
        t.sort();
    }
     
    public void sort(){
        Map treeMap = new TreeMap();
        treeMap.put("c", "ccccc"); 
        treeMap.put("a", "aaaaa"); 
        treeMap.put("b", "bbbbb"); 
        treeMap.put("d", "ddddd"); 
        Set s = treeMap.keySet();
        for (String key : s) { 
            System.out.println(key+" : "+treeMap.get(key)); 
        } 
    }
}

public class MapSortDemo {

    public static void main(String[] args) {

        Map map = new TreeMap();

        map.put("KFC", "kfc");
        map.put("WNBA", "wnba");
        map.put("NBA", "nba");
        map.put("CBA", "cba");

        Map resultMap = sortMapByKey(map);    //按Key进行排序
//        Map resultMap = sortMapByValue(map); //按Value进行排序

        for (Map.Entry entry : resultMap.entrySet()) {
            System.out.println(entry.getKey() + " " + entry.getValue());
        }
    }
    
    /**
     * 使用 Map按value进行排序
     * @param map
     * @return
     */
    public static Map sortMapByValue(Map oriMap) {
        if (oriMap == null || oriMap.isEmpty()) {
            return null;
        }
        Map sortedMap = new LinkedHashMap();
        List> entryList = new ArrayList>(
                oriMap.entrySet());
        Collections.sort(entryList, new MapValueComparator());

        Iterator> iter = entryList.iterator();
        Map.Entry tmpEntry = null;
        while (iter.hasNext()) {
            tmpEntry = iter.next();
            sortedMap.put(tmpEntry.getKey(), tmpEntry.getValue());
        }
        return sortedMap;
    }
}