JavaScript 文字列が単一の文字に分割され、合計が 10 を超えない場合、最終値を見つけます

<script type="text/javascript"> 
var str = "19871229"; 
var count = 0; 
for(var i = 0 ; i < str.length ; i++) 
count += parseInt(str.charAt(i)); 
alert (getResult(count)); 
function getResult(x) { 
var a = Math.floor(x/10); 
var b = x%10; 
if(a+b > 10) 
return getResult(a+b); 
else 
return (a+b); 
} 
</script>

<script> 
var birthday = "1982512"; 
BirthSum(birthday); 
function BirthSum(str){ 
var bsum = 0; 
var arr = str.toString().split(&#39;&#39;); 
for(var i = 0; i<arr.length; i++){ 
bsum += parseInt(arr[i]); 
} 
if(bsum > 10){ 
BirthSum(bsum); 
}else{ 
alert(bsum); 
} 
} 
</script>

<script type="text/javascript"> 
var num="11111232"; 
var sum=0; 
while(true){ 
for(var i=0;i<num.length;i++){ 
sum+=parseInt(num.charAt(i)); 
} 
if(sum<11) 
break; 
else{ 
num=sum+""; 
sum=0; 
} 
} 
alert(sum); 
</script>

@echo off 
color 0A 
echo 请输入数字: 
set /p age= 
echo --------------- 
title %age% 
set sum=0 
set get=0 
set call_num=0 
::计算字符串长度 
:begin 
set /a call_num+=1 
echo 第%call_num%次循环 
set str=%age% 
set num=0 
:next1 
if not "%str%"=="" ( 
set /a num+=1 
set "str=%str:~1%" 
goto next1 
) 
echo 当前数字%age% 
@echo. 
set i=%num% 
:loop 
set /a i-=1 
set "get=%age:~-1%" 
set "age=%age:~0,-1%" 
set /a sum+=get 
if not "%age%"=="" ( 
goto loop 
) 
if %sum% gtr 10 ( 
set age=%sum% 
set sum=0 
goto begin 
) 
echo 最终结果:%sum% 
pause