Pour le comprendre, considérez les données du tableau "Étudiants" comme indiqué ci-dessous -
mysql> Select * from Students; +----+-----------+-----------+----------+----------------+ | id | Name | Country | Language | Course | +----+-----------+-----------+----------+----------------+ | 1 | Francis | UK | English | Literature | | 2 | Rick | USA | English | History | | 3 | Correy | USA | English | Computers | | 4 | Shane | France | French | Computers | | 5 | Validimir | Russia | Russian | Computers | | 6 | Steve | Australia | English | Geoinformatics | | 7 | Rahul | India | Hindi | Yoga | | 8 | Harshit | India | Hindi | Computers | | 9 | Harry | NZ | English | Electronics | +----+-----------+-----------+----------+----------------+ 9 rows in set (0.00 sec)
Maintenant, supposons que nous voulions savoir combien d'étudiants appartiennent aux États-Unis, au Royaume-Uni, en Nouvelle-Zélande, en Inde, en Russie, en France, etc. alors nous pouvons utiliser la colonne Country dans l'instruction CASE comme indiqué ci-dessous -
mysql> Select SUM(CASE WHEN country = 'USA' THEN 1 ELSE 0 END) AS USA, -> SUM(CASE WHEN country = 'UK' THEN 1 ELSE 0 END) AS UK, -> SUM(CASE WHEN country = 'INDIA' THEN 1 ELSE 0 END) AS INDIA, -> SUM(CASE WHEN country = 'Russia' THEN 1 ELSE 0 END) AS Russia, -> SUM(CASE WHEN country = 'France' THEN 1 ELSE 0 END) AS France, -> SUM(CASE WHEN country = 'NZ' THEN 1 ELSE 0 END) AS NZ, -> SUM(CASE WHEN country = 'Australia' THEN 1 ELSE 0 END) AS Australia -> From Students; +------+------+-------+--------+--------+------+-----------+ | USA | UK | INDIA | Russia | France | NZ | Australia | +------+------+-------+--------+--------+------+-----------+ | 2 | 1 | 2 | 1 | 1 | 1 | 1 | +------+------+-------+--------+--------+------+-----------+ 1 row in set (0.07 sec)
Ce qui précède est le contenu détaillé de. pour plus d'informations, suivez d'autres articles connexes sur le site Web de PHP en chinois!