php的json_encode函数问题，phpjson_encode函数
php的json_encode函数问题：
$ary = [];
$ary[0] = 'a';
$ary[1] = 'b';
echo json_encode($ary) . '
';
echo json_encode($ary, JSON_FORCE_OBJECT);
结果：
["a","b"]
{"0":"a","1":"b"}
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