python将人民币转换大写的脚本代码

def Num2MoneyFormat( change_number ):
    """
    .转换数字为大写货币格式( format_word.__len__() - 3 + 2位小数 )
    change_number 支持 float, int, long, string
    """
    format_word = ["分", "角", "元",
               "拾","百","千","万",
               "拾","百","千","亿",
               "拾","百","千","万",
               "拾","百","千","兆"]

    format_num = ["零","壹","贰","叁","肆","伍","陆","柒","捌","玖"]
    if type( change_number ) == str:
        # - 如果是字符串,先尝试转换成float或int.
        if '.' in change_number:
            try:    change_number = float( change_number )
            except: raise ValueError, '%s   can\'t change'%change_number
        else:
            try:    change_number = int( change_number )
            except: raise ValueError, '%s   can\'t change'%change_number

    if type( change_number ) == float:
        real_numbers = []
        for i in range( len( format_word ) - 3, -3, -1 ):
            if change_number >= 10 ** i or i                 real_numbers.append( int( round( change_number/( 10**i ), 2)%10 ) )

    elif isinstance( change_number, (int, long) ):
        real_numbers = [ int( i ) for i in str( change_number ) + '00' ]

    else:
        raise ValueError, '%s   can\'t change'%change_number

    zflag = 0                       #标记连续0次数，以删除万字，或适时插入零字
    start = len(real_numbers) - 3
    change_words = []
    for i in range(start, -3, -1):  #使i对应实际位数，负数为角分
        if 0 real_numbers[start-i] or len(change_words) == 0:
            if zflag:
                change_words.append(format_num[0])
                zflag = 0
            change_words.append( format_num[ real_numbers[ start - i ] ] )
            change_words.append(format_word[i+2])

        elif 0 == i or (0 == i%4 and zflag             change_words.append(format_word[i+2])
            zflag = 0
        else:
            zflag += 1

    if change_words[-1] not in ( format_word[0], format_word[1]):
        # - 最后两位非"角,分"则补"整"
        change_words.append("整")

    return ''.join(change_words)

Python 把金额小写转换成大写2

功能将小于十万亿元的小写金额转换为大写