Home > php教程 > PHP源码 > 封装 Twitter 访问的 PHP 类

封装 Twitter 访问的 PHP 类

PHP中文网
Release: 2016-06-01 14:32:35
Original
1148 people have browsed it

跳至

<?php

class Twitter {

    /**
     * Method to make twitter api call for the users timeline in XML
     *
     * @access private
     * @param $twitter_id, $num_of_tweets
     * @return $xml
     */
    private function api_call($twitter_id, $num_of_tweets) {
        $c = curl_init();

        curl_setopt($c, CURLOPT_URL, "http://twitter.com/statuses/user_timeline/$twitter_id.xml?count=$num_of_tweets");
        curl_setopt($c, CURLOPT_RETURNTRANSFER, 1);
        curl_setopt($c, CURLOPT_CONNECTTIMEOUT, 3);
        curl_setopt($c, CURLOPT_TIMEOUT, 5);

        $response = curl_exec($c);
        $response_info = curl_getinfo($c);

        curl_close($c);

        if (intval($response_info[&#39;http_code&#39;]) == 200) {
            $xml = new SimpleXMLElement($response);

            return $xml;
        } else {
            return false;
        }
    }

    /**
     * Method to add hyperlink html tags to any urls, twitter ids or hashtags in tweet
     *
     * @access private
     * @param $text
     * @return $text
     */
    private function process_links($text) {
        $text = utf8_decode($text);
        $text = preg_replace(&#39;@(https?://([-\w\.]+)+(d+)?(/([\w/_\.]*(\?\S+)?)?)?)@&#39;, &#39;$1&#39;, $text);
        $text = preg_replace("#(^|[\n ])@([^ \"\t\n\rapi_call($twitter_id, $num_of_tweets)) {
            $result = $cont_o;

            foreach ($twitter_xml->status as $key => $status) {
                if ($include_replies == true | substr_count($status->text, "@") == 0 | strpos($status->text, "@") != 0) {
                    $tweet = $this->process_links($status->text);

                    $result .= $tweet_o . $tweet . $tweet_c . $detail_o . date(&#39;D jS M y H:i&#39;, strtotime($status->created_at)) . $detail_c;
                }
            }

            $result .= $cont_c;
        } else {
            $result .= $cont_o . $tweet_o . "Twitter seems to be unavailable at the moment." . $tweet_c . $cont_c;
        }

        return $result;
    }

}
Copy after login

                   

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Recommendations
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template