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Arithmetic operator precedence order in java

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Release: 2024-04-26 01:00:23
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Priority order of arithmetic operators in Java: unary operators ( , --) multiplication and division operators (*, /, %) addition and subtraction operators ( , -)

Arithmetic operator precedence order in java

Priority order of arithmetic operators in Java

Answer:
In Java, Arithmetic The priority order of operators is as follows:

1. Unary operators

  • , --:Highest priority
  • , -: positive, negative

2. Multiplication and division operators

  • *,/,%:Higher priority

3. Addition and subtraction operators

  • , -:Lower priority

Expand answer:

Unary operators have the highest precedence, which means they are executed first. For example:

<code class="java">int num = 10;
int result1 = ++num; // result1 = 11, num = 11
int result2 = -num; // result2 = -11</code>
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Next, the multiplication, division, and modulo operators have higher precedence. For example:

<code class="java">int num1 = 10;
int num2 = 3;
int result3 = num1 * num2; // result3 = 30
int result4 = num1 / num2; // result4 = 3
int result5 = num1 % num2; // result5 = 1</code>
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Finally, addition and subtraction operators have lower precedence. They are executed after all other operators. For example:

<code class="java">int num3 = 10;
int num4 = 5;
int result6 = num3 + num4; // result6 = 15
int result7 = num3 - num4; // result7 = 5</code>
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Note:

  • If two operators have the same precedence, they are executed from left to right.
  • You can use parentheses to change the precedence of operators.

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