php editor Zimo is here to introduce a common code fragment: f = Foo(value). What this code does is creates a Foo object named f and passes value as a parameter to its constructor. In this way, we can use the Foo object in the program and operate and process it. A Foo object may be an instance of a class, which may have various properties and methods used to implement specific functionality. By creating an object and passing parameters, we can dynamically initialize the object's properties as needed to meet the program's requirements. This is a commonly used code snippet that can be used in many different programming scenarios.
I found the implementation of thedatabase/sql.Scanner
interface, but I don’t quite understand it?
can be compiled
The part I get isFoo
is an integer and it has methodScan
Scan
method returnserror
, but how to returnfmt.Errorf("Invalid database type: %T %v", value, value)
? Isn't this a bug or is it?
*f = Foo(value)
What does it do? When you pass this type torows.Scan()
, does it callFoo.Scan()
? If the type is expectedint64
it will call itselfFoo(value)
?
type Foo int // Scan implements the database/sql.Scanner interface func (f *Foo) Scan(value interface{}) error { switch value := value.(type) { case int64: *f = Foo(value) default: return fmt.Errorf("Invalid database type: %T %v", value, value) } return nil }
fmt.Errorf(format, args)
Returns the error value created usingerrors.New(str)
, wherestr
is the format String (your error message).
Line*f = Foo(value)
Converts theint64
value to theFoo
type and assigns it to the method receiver (notef
is a pointer).
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