Idiomatic way to iterate over a string and replace values ​​in the original string with mapped values

php editor Xinyi brings an idiomatic method of iterating a string and replacing the values ​​in the original string with the mapped value. This method can help developers simplify the string operation process and improve development efficiency. By using a mapped array, developers can define a set of key-value pairs and then use an iterative method to replace specific values ​​in the original string with mapped values. This method is not only simple and easy to understand, but also can be applied to various scenarios, such as data processing, text replacement, etc. Both beginners and experienced developers can benefit from this approach to handle string operations quickly and efficiently.

Question content

I have a working solution about iterating a string and mapping rune to a map

package main

import (
    "fmt"
)

func main() {

    numToString := map[rune]string{
        '0': "zero",
        '1': "one",
        '2': "two",
        '3': "three",
        '4': "four",
        '5': "five",
        '6': "six",
        '7': "seven",
        '8': "eight",
        '9': "nine",
    }

    testStr := "one two 3 four"
    newStr := ""
    for _, char := range testStr {
        if val, ok := numToString[char]; ok {
            newStr += val
            continue
        }
        newStr += string(char)
    }
    // prints one two three four
    fmt.Println(string(newStr))
}

This suits my wishes... but I'm curious about a cleaner way (if possible) rather than allocating a whole new string to build from the original string. If I could modify the original content in-place while iterating, I would prefer to do so.

This is the playground

Solution

Use strings.Replacer to replace strings.

var numToString = strings.NewReplacer(
    "0", "zero",
    "1", "one",
    "2", "two",
    "3", "three",
    "4", "four",
    "5", "five",
    "6", "six",
    "7", "seven",
    "8", "eight",
    "9", "nine").Replace

func main() {
    testStr := "one two 3 four"
    newStr := numToString(testStr)
    fmt.Println(newStr)
}

//m.sbmmt.com/link/7d420e2b2939762031eed0447a9be19f

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