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Turn your old Python web application into WSGI ready and Apache

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Release： 2024-02-09 15:33:03

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将旧的 Python Web 应用程序转变为 WSGI 就绪和 Apache

Question content

I have an ancient web application written in python. It's basically a bunch of .py files. For example:

display.py:

import cgi
import re
import string
import operator
from urllib.parse import urlparse
from errors import herigean
from routines import *

error = false

query = cgifieldstoragetodict(cgi.fieldstorage())
opening_index = 0 # flag to indicate whether we're opening the index page
if ('what' not in query):
        query['what'] = 'index'
if 'fs' not in query:
        query['fs'] = str(default_font_size)

# open page to display
try:
        fil = open('html/'+query['what']+'.fmt')
        textlines = fil.read()
        queryreg = re.compile('query:fs:query')
      textlines = queryreg.sub(query['fs'],textlines)
        fil.close()
except ioerror:
        error = true

if query['what'] == 'about':
        try:
                fil = open('legal/lgpl-3.0.txt')
                lgpl = fil.read()
                fil.close()
                fil = open('legal/gpl.txt')
                gpl = fil.read()
                fil.close()
                fil = open('html/availability.fmt')
                availability = fil.read()
                fil.close()
        except ioerror:
                error = true
if query['what'] == 'corpus':
        try:
                fil = open('html/availability.fmt')
[...]
if error:
        herigean()
else:
        print(frontmatter)

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etc

How to run it behind an apache proxy using mod_wsgi installed in a virtual environment? Now I have a pythong 3.11 virtual environment with mod_wsgi-express 5 installed. I can successfully run test.py using the following command:

mod_wsgi-express start server test.py

def application(environ, start_response):
    start_response('200 ok', [('content-type', 'text/html')])
    return [b'hello, world!']

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How do I run my old python application? Do I just wrap each .py file in def application(environ, start_response):? Any help would be greatly appreciated.

Add to:

www.index.html for this application. There is a <meta http-equiv="refresh" content="0;url=display.py?what=index" />. This is how it is currently served.

Additionalii

I can't get the output: when using

def application(environ, start_response):
    start_response('200 OK', [('Content-Type', 'text/html')])
    [...]
    return print(frontmatter)

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I get the entire html in the logs, then typeerror: 'nonetype' object is not iterable and an internal server error on the browser.

Correct answer

I should use yield bytes(html) instead of print.

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