How to let golang distinguish between XML elements with namespace and without namespace?

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Release: 2024-02-09 12:00:09
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How to let golang distinguish between XML elements with namespace and without namespace?

php editor Zimo will share with you how to let golang distinguish XML elements with namespaces and without namespaces. When dealing with XML data, namespace is an important concept that can help us better organize and distinguish different XML elements. This article will introduce how to use golang's xml package to parse and process XML elements with and without namespaces, and provide some sample codes for practical applications. Whether you are a beginner or an experienced developer, you will gain valuable knowledge and tips from this article. Let’s explore this fun and practical topic together!

Question content

Suppose I have the following xml data:

  http://sampleurl.com    //xmldata
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I use this structure to decode it:

type response struct { xmlname xml.name `xml:"resp"` image []struct { url string `xml:"url"` } `xml:"image"` itunesimage struct { url string `xml:"url,attr"` } `xml:"http://www.itunes.com/dtds/podcast-1.0.dtd image"` }
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I have this code:

var resp Response err := xml.Unmarshal([]byte(xmlData), &resp) if err != nil { fmt.Printf("Error decoding XML: %s\n", err) return } for _, img := range resp.Image{ if img.URL != "" { //, not  } }
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Processing decoding

The problem I'm having is that it looks likeimage []structthinksandare bothelements because they all have "images". To filter out, the approach I used was to have everyone in theimage []structcheck if theirurlwas an empty string ( Because foritsurlis an attribute).

Another approach is to write my ownunmarshalfunction to differentiate between xml elements with and withoutitunesnamespace. Basically I wantimage []structto save only the element

I wonder if go has some built-in functionality to differentiate? Or do I have to write code to filter out?

Solution

Please note that field order is important.itunesimagehas a more specific tag, so it should come beforeimage.

package main import ( "encoding/xml" "fmt" ) func main() { type response struct { xmlname xml.name `xml:"resp"` itunesimage struct { url string `xml:"url,attr"` } `xml:"http://www.itunes.com/dtds/podcast-1.0.dtd image"` image []struct { url string `xml:"url"` } `xml:"image"` } xmldata := `   http://sampleurl.com    ` var resp response err := xml.unmarshal([]byte(xmldata), &resp) if err != nil { fmt.printf("error decoding xml: %s\n", err) return } fmt.printf("itunesimage: %v\n", resp.itunesimage) fmt.printf("images: %v\n", resp.image) }
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If you only need thein theimage/urltag, you can define theresponsestructure like this:

type response struct { xmlname xml.name `xml:"resp"` image []string `xml:"image>url"` }
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Regarding the general question in the title (how to make golang differentiate between xml elements with and without namespaces?), you can capture the element name using a field calledxmlname, and check that field Member ofspace. See demo below:

package main import ( "encoding/xml" "fmt" ) func main() { type response struct { xmlname xml.name `xml:"resp"` image []struct { xmlname xml.name url string `xml:"url"` } `xml:"image"` } xmldata := `   http://sampleurl.com   http://sampleitunesurl.com/   ` var resp response err := xml.unmarshal([]byte(xmldata), &resp) if err != nil { fmt.printf("error decoding xml: %s\n", err) return } for _, img := range resp.image { fmt.printf("namespace: %q, url: %s\n", img.xmlname.space, img.url) } }
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The output of the above demonstration is:

namespace: "", url: http://sampleUrl.com namespace: "http://www.itunes.com/dtds/podcast-1.0.dtd", url: http://sampleItunesUrl.com/
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source:stackoverflow.com
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