It is known that function f(x) passes through point A(2, 2^(34*25*4))

1. The curve of the known function fx=x^34x^2 5x4 passing through point A(2, 2), what is the tangent equation of fx?

To require the tangent equation of the curve at point A(2, 2), the following steps need to be performed:

1. 1.Derivation:Calculate the derivative of the function fx, i.e. fx', which will give the slope of the curve at any point.

2. 2.Substituting point A:Substituting the x value of 2 into the derivative fx', we get the slope of the tangent line at point A.

3. 3.Tangent equation:Use point-slope formula or general formula to substitute the obtained slope and point A(2, 2) to get the tangent equation .

For example, if the derivative is fx', the tangent equation at point A(2, 2) can be expressed as y = fx'(2)(x - 2) 2.

2. The tangent line of function fx=x^2 bx ce^x at point P(0, f0)?

For the function fx=x^2 bx ce^x, solve the tangent equation at point P(0, f0). The steps are as follows:

1. 1.Derivative:Calculate the derivative of function fx, that is, fx'.

2. 2.Substituting point P:Substituting the x value of 0 into the derivative fx', we get the slope of the tangent line at point P.

3. 3.Tangent equation:Use point slope formula or general formula to substitute the obtained slope and point P(0, f0) to get the tangent equation .

For example, if the derivative is fx', the tangent equation at point P(0, f0) can be expressed as y = fx'(0)(x - 0) f0.

Summary

The general steps to solve the tangent equation of a curve at a specific point include calculating the derivative, substituting into the specific point to obtain the slope, and then using the point slope formula or the general formula to obtain Tangent equation. In these two problems, attention needs to be paid to the specific calculations when deriving the derivation and substitution points.

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