In almost all modern programming languages, we can find some logarithmic functions such as natural logarithm, base 2 logarithm, base 10 logarithm, etc. But sometimes we need to calculate logarithms of different bases that are not in the given library functions. To achieve this we can use a simple logarithmic formula. In this article, we will see how to calculate logarithmic value in C using a given number and a given base.
Suppose we have taken a number x, its base is k, which has also been given. The formula is as follows: The translation of follow −
is: follow −$$\mathrm{log_{k}\left ( x \right )=\frac{log_{m}\left ( x \right )}{log_{m}\left ( k \right )}}$ $
where m is any known (available base)
C The cmath library provides the log10() method for finding the base 10 logarithm of a given number. us The same function can be used to calculate the logarithm of a given base k. The syntax used is: An example of log10() is as follows −
#include < cmath > Log10()
Read two numbers x and k
res := (use log10(x) to find the base 10 logarithm of x) / (use log10(k) to find the base 10 logarithm of k)
return res
#include#include using namespace std; float solve( int x, int k){ float answer; answer = log10( x ) / log10( k ); return answer; } int main(){ cout << "Log base 8 for input x = 512 is: " << solve( 512, 8 ) << endl; cout << "Log base 9 for input x = 59049 is: " << solve( 59049, 9 ) << endl; cout << "Log base 2 for input x = 1024 is: " << solve( 1024, 2 ) << endl; cout << "Log base 4 for input x = 256 is: " << solve( 256, 4 ) << endl; }
Log base 8 for input x = 512 is: 3 Log base 9 for input x = 59049 is: 5 Log base 2 for input x = 1024 is: 10 Log base 4 for input x = 256 is: 4
In the cmath library of C, the log2() method allows users to find the logarithm with base 2 given number. The same function can be used to compute the logarithm of a specified base k The following syntax is used to use log2() −
#include < cmath > Log2()
Read two numbers x and k
res := (use log2( x ) to find the base 2 logarithm of x) / (use log2( k ) to find the base 2 logarithm of x)
return res
#include#include using namespace std; float solve( int x, int k){ float answer; answer = log2( x ) / log2( k ); return answer; } int main(){ cout << "Log base 8 for input x = 512 is: " << solve( 512, 8 ) << endl; cout << "Log base 9 for input x = 59049 is: " << solve( 59049, 9 ) << endl; cout << "Log base 2 for input x = 1024 is: " << solve( 1024, 2 ) << endl; cout << "Log base 4 for input x = 256 is: " << solve( 256, 4 ) << endl; }
Log base 8 for input x = 512 is: 3 Log base 9 for input x = 59049 is: 5 Log base 2 for input x = 1024 is: 10 Log base 4 for input x = 256 is: 4
In the C cmath library, the natural logarithm log() method allows the user to find the logarithm Use base 'e' for the given number. Logarithms can be calculated using a specified base k Same functionality. The following syntax is used to use the log() function −
#include < cmath > log()
Read two numbers x and k
res := (use log(x) to find the logarithm of x with base e) / (use log(k) to find the logarithm of x with base e)
return res
#include#include using namespace std; float solve( int x, int k){ float answer; answer = log( x ) / log( k ); return answer; } int main(){ cout << "Log base 8 for input x = 512 is: " << solve( 512, 8 ) << endl; cout << "Log base 9 for input x = 59049 is: " << solve( 59049, 9 ) << endl; cout << "Log base 2 for input x = 1024 is: " << solve( 1024, 2 ) << endl; cout << "Log base 4 for input x = 256 is: " << solve( 256, 4 ) << endl; }
Log base 8 for input x = 512 is: 3 Log base 9 for input x = 59049 is: 5 Log base 2 for input x = 1024 is: 10 Log base 4 for input x = 256 is: 4
Using the logarithmic formula of a given base can get the logarithmic result, We use any known base logarithm method on a given number x and divide it by The logarithmic base using a known value as the new base as input. In this article we use Three known existing logarithmic functions are log10(), log2() and log() [natural logarithm] Generates results for the given numbers and their given base.
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