How to update view in mysql-Mysql Tutorial-php.cn

1. Some views are not updatable because updates to these views cannot be uniquely and meaningfully converted to the corresponding basic tables.

2. Generally speaking, rows and rows subset views can be updated. In addition to column subset views, it is theoretically possible to update some views.

Example

-- 创建视图 ldq_t1 CREATE VIEW ldq_t1 AS SELECT * FROM t3 WHERE id1 > 10 WITH CHECK OPTION ; -- 查询ldq_t1中的所有结果 SELECT * FROM ldq_t1; -- 创建视图 ldq_t2 CREATE VIEW ldq_t2 AS SELECT * FROM ldq_t1 WHERE id1 < 30 WITH LOCAL CHECK OPTION ; -- 创建视图 ldq_t3 CREATE VIEW ldq_t3 AS SELECT * FROM ldq_t1 WHERE id1 < 30 WITH CHECK OPTION ; -- 更新视图ldq_t2（只有ldq_t2中存在的数据都可以更新） SELECT * FROM ldq_t2; -- 查看ldq_t2当前记录 UPDATE ldq_t2 SET id1=5 WHERE id2=22; -- 可以执行成功 UPDATE ldq_t2 SET id1=35 WHERE id2=22; -- 将会报错CHECK OPTION failed(因为执行该语句之后，id2=22记录将从ldq_t2消失) UPDATE ldq_t2 SET id1=28 WHERE id2=22; -- 可以执行成功 -- 更新ldq_t3 SELECT * FROM ldq_t3; UPDATE ldq_t3 SET id1=5 WHERE id2=22; -- 将会报错CHECK OPTION failed（因为数据更新之后，必须还要保证其仍然在ldq_t3和ldq_t1之中,该语句执行后id2=22记录将从ldq_t1消失） UPDATE ldq_t3 SET id1=15 WHERE id2=22; -- 能够执行成功 UPDATE ldq_t3 SET id1=35 WHERE id2=22; -- 将会报错CHECK OPTION failed（因为执行该语句之后，id2=22记录将从ldq_t3消失） DELETE FROM ldq_t3 WHERE id2=22; -- 执行成功

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