How to implement alphabetical sorting in strings in java

Question requirements

Java implements alphabetical sorting in strings and outputs the sorted results

Analysis

1. Create a string, assign a value and Store characters into an array one by one.

String str = "chenughonghuiaikuangwantong1314";
    char[] chars = str.toCharArray();

2. Sort it

The sort method is a static method in the Arrays class and can be called directly using the class name.

static void sort(type [] a)

• Sort the specified type array in ascending numerical order.

• The default is ascending order

static void sort(type [] a, int fromIndex, int toIndex)

Sort the specified range of the specified array in ascending numerical order.

• type can be specified as int, float, double, long, byte, etc.

• ##a - The array to be sorted

• fromIndex - The index of the first element to be sorted (inclusive)

• toIndex-The index of the last element to be sorted (exclusive)

3. Print the loop through the for loop

for (int i = 0; i < chars.length; i++) {
        System.out.print(chars[i]);
    }

for (int i = chars.length - 1; i >= 0; i--) {
        System.out.print(chars[i]);
    }

import java.util.Arrays;

public class characterSorting {
    public static void main(String[] args) {
        String str = "chenughonghuiaikuangwantong1314";
        System.out.println("原字符串："+str);
        char[] chars = str.toCharArray();
        Arrays.sort(chars);
        //正序遍历输出
        System.out.println("正序输出：");
        for (int i = 0; i < chars.length; i++) {
            System.out.print(chars[i]);
        }
        //倒序遍历输出
        System.out.println();
        System.out.println("倒序输出：");
        for (int i = chars.length - 1; i >= 0; i--) {
            System.out.print(chars[i]);
        }
    }
}

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Running result

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