Table of Contents
Go language split method
Usage example
Notes
Home Backend Development Golang What is the use of split method in go language

What is the use of split method in go language

Jan 28, 2023 pm 01:37 PM
golang go language split

In the Go language, the Split() method is used to split a string. You can use delimiters to divide the string into a list of substrings, and the substrings are returned in the form of slices. Split() is a method of the strings package. You need to import the strings package before using it. The syntax is "strings.Split (string to be split, delimiter)".

What is the use of split method in go language

The operating environment of this tutorial: Windows 7 system, GO version 1.18, Dell G3 computer.

Go language split method

In Go, the Split() function (contained in the strings package) uses delimiters to divide a string into a list of substrings. The substring is returned as a slice.

Syntax

Need to import the strings package

strings.Split(s, sep)
ParametersDescription Remarks
sString to be splitParameters of string type
sepSeparator

String type parameters

Return value

Returns a string slice.

Usage example

The Split() function splits the string according to the delimiter. After cutting, a string slice is returned. The slice len and cap values ​​are equal to the number of delimiters in the original string 1 (this is only true if s is not an empty string).

package main

import (
	"fmt"
	"strings"
)

func main() {
	demo := "I&love&Go,&and&I&also&love&Python."
	string_slice := strings.Split(demo, "&")

	fmt.Println("result:",string_slice)
	fmt.Println("len:",len(string_slice))
	fmt.Println("cap:", cap(string_slice))
}

The running results are as follows:

result: [I love Go, and I also love Python.]
len: 8
cap: 8

Notes

1. When the delimiter does not exist in the original string When

When the delimiter does not exist in the original string, the Split() function only converts the original string into a string slice with both len and cap values ​​​​1.

package main

import (
	"fmt"
	"strings"
)

func main() {
	demo := "I love Go, and I also love Python."
	string_slice := strings.Split(demo, "&")

	fmt.Println("result:",string_slice)
	fmt.Println("len:",len(string_slice))
	fmt.Println("cap:", cap(string_slice))
}

The running results are as follows:

result: [I love Go, and I also love Python.]
len: 1
cap: 1

2. When the delimiter is an empty string

When the delimiter is When the string is empty, the Split() function splits each character in the string into a separate element.

package main

import (
	"fmt"
	"strings"
)

func main() {
	demo := "Go"
	string_slice := strings.Split(demo, "")

	fmt.Println("result:",string_slice)
	fmt.Println("len:",len(string_slice))
	fmt.Println("cap:", cap(string_slice))
}

Run result:

result: [G o]
len: 2
cap: 2

3. The parameters are all empty strings

When the two parameters of the Split() function When both parameters are empty strings (that is, s and sep are both empty strings), the Split() function returns an empty string slice with both len and cap values ​​​​0.

package main

import (
	"fmt"
	"strings"
)

func main() {
	demo := ""
	string_slice := strings.Split(demo, "")

	fmt.Println("result:",string_slice)
	fmt.Println("len:",len(string_slice))
	fmt.Println("cap:", cap(string_slice))
}

Run result:

result: []
len: 0
cap: 0

4. When s is an empty string and sep is not an empty string

Different from the previous scenario, in this case the result is still a string slice, but the len and cap values ​​of the string slice are 1 (instead of 0 like in the previous scenario). The returned result is a string slice containing an empty string.

package main

import (
	"fmt"
	"strings"
)

func main() {
	demo := ""
	string_slice := strings.Split(demo, "*")

	fmt.Println("result:",string_slice)
	fmt.Println("len:",len(string_slice))
	fmt.Println("cap:", cap(string_slice))

	element := string_slice[0]
	fmt.Printf("string_slice[0]:%s, type:%T, len():%d\n",
		element, element, len(element),)

	fmt.Println("element == \"\"?", element == "")
}

Running result:

result: []
len: 1
cap: 1
string_slice[0]:, type:string, len():0
element == ""? true

5. The returned string slice no longer contains the delimiter

[Related Recommended: Go video tutorial, Programming teaching

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