


Examples to explain how to batch modify file names in Python
本篇文章给大家带来了关于python视频教程的相关知识,其中主要介绍了关于批量修改文件名的相关问题,包括了在原有的名字前中后批量加字、所有文件重新命名并添加序号等等内容,下面一起来看一下,希望对大家有帮助。
推荐学习:python
一、在原有的名字前中后批量加字
随意一点,这是我刚刚新建的文件夹和我存放的路径。
我们来看看代码,我都详细注释了。
import os #导入模块 filename = 'C:\\Users\\Administrator\\Desktop\\123' #文件地址 list_path = os.listdir(filename) #读取文件夹里面的名字 for index in list_path: #list_path返回的是一个列表 通过for循环遍历提取元素 name = index.split('.')[0] #split字符串分割的方法 , 分割之后是返回的列表 索引取第一个元素[0] kid = index.split('.')[-1] #[-1] 取最后一个 path = filename + '\\' + index new_path = filename + '\\' + name + '彦祖你来了啊' + '.' + kid os.rename(path, new_path) #重新命名 print('修改完成')
如果你照抄,原有的名字没动,这个代码只会在原有的名字后面添加你想取的名字+原有的名字。
如果你要在前面添加,在第八行把 + name 删了。
如果你要在后面添加,第八行把+ kid 删了。
二、所有文件重新命名并添加序号
这种的话,直接把原来的名字都给改掉,在后面添加序号,来我们先准备要改的文件。
import os #导入模块 filename = 'C:\\Users\\Administrator\\Desktop\\123' #文件地址 list_path = os.listdir(filename) #读取文件夹里面的名字 count = 1for index in list_path: path = filename + '\\' + index # 原本文件名 new_path = filename + '\\' + f'彦祖,你又来看我文章了{count}' print(new_path) os.rename(path, new_path) count += 1print('修改完成')
代码的话,大致跟前面差不多,没怎么注释了,就是加上序号和覆盖原本的名字。看看效果
当然序号的话,也可以放在后面,把 彦祖,你又来看我文章了{count}换成 {count}彦祖,你又来看我文章了 前后换一下就行了。
三、导入Excel数据批量修改为文件名
这个的话,咱们首先要有Excel数据,没有的话瞎编一个。
然后要改名的文件,这回我用的是文本文档,因为等下还有个小技巧。
代码
import os import xlrd count = 1 path = "C:\\Users\\Administrator\\Desktop\\123" #文件所在文件夹 expath = "C:\\Users\\Administrator\\Desktop\\18.xls"#Excel表所在文件夹 x1 = xlrd.open_workbook(expath)#读取excel sheet1 = x1.sheet_by_name("Sheet1")#读取sheet1 idlist = sheet1.col_values(0)#存放第一列 xylist = sheet1.col_values(1)#存放第二列 filelist = os.listdir(path)#读取文件目录for files in filelist:#遍历文件目录 Olddir = os.path.join(path,files)#旧的文件位置 os.renames(Olddir,os.path.join(path,str(int(idlist[count]))+" "+xylist[count]))#新的文件位置 count = count +1#计数指针后移
OK 我们来试试看
可能有人要问了,说好的小技巧呢? 莫慌,来了来了~
你们有没有注意到我修改后的文件是不是不一样的,没得格式。
所以我们还得加上个格式,至于是什么格式,你原本的文件是什么格式就加上什么格式。
我们在新的文件位置那行最后,括号里面加上+".txt" 我这里是txt文件我就加txt了。
推荐学习:python视频教程
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