Home > Backend Development > PHP Tutorial > PHP algorithm exercise 2: Find the absolute difference between n and the specified number

PHP algorithm exercise 2: Find the absolute difference between n and the specified number

藏色散人
Release: 2023-04-10 14:02:02
Original
2873 people have browsed it

In "PHP Algorithm Exercise 1: Calculate the sum of two numbers and three times the sum", I introduced you to the first question of PHP arithmetic exercise. I believe everyone has mastered it. So the theme of today’s article is somewhat similar to it, I hope everyone can master it quickly!

We used to find the sum, now we find the difference, let’s do it one by one~

The specific question of this article is "Write a PHP program to get the absolute difference between n and the specified value .If n is greater than this specified value, three times the absolute difference is returned."

You can practice it locally, and then look at my method below:

The PHP code is as follows:

<?php

function test($n)
{
    $x = 50;

    if ($n > $x)
    {
        return ($n - $x)*3;
    }
    return $x - $n;
}
echo test(53)."<br>";
echo test(30)."<br>";
echo test(50)."<br>";
Copy after login

The output calculation result is:

PHP algorithm exercise 2: Find the absolute difference between n and the specified number

In the above code, the specified value we gave is 50, and then the if statement is used to determine whether n is greater than 50. If n is greater than 50, three times the absolute difference is returned, otherwise it is returned its absolute difference. The key arithmetic code parts here are "($n - $x)*3;" and "$x - $n;".

In this example, the first n we gave is 53, then 53 is greater than 50, and the result is naturally to return (53-50)*3=9;

The second one n is 30, which is less than 50, and the result is "50-30=20";

The third n is 50, which is equal to 50, and the result is naturally 0.

In the above code, a function is used to customize a test method. Needless to say, it mainly depends on the understanding and mastery of if judgment statements and PHP operators.

A brief introduction to the conditional statements provided in PHP:

if 语句 - 在条件成立时执行代码
if...else 语句 - 在条件成立时执行一块代码,条件不成立时执行另一块代码
if...elseif....else 语句 - 在若干条件之一成立时执行一个代码块
switch 语句 - 在若干条件之一成立时执行一个代码块
Copy after login

Finally, I would like to recommend the latest free course on our platform "Entering the World of PHP from 0" ~Come and learn!

The above is the detailed content of PHP algorithm exercise 2: Find the absolute difference between n and the specified number. For more information, please follow other related articles on the PHP Chinese website!

Related labels:
php
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template