How to implement query function in php

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Release: 2023-03-06 15:52:01
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How to implement the query function in php: first create the front-end file and PHP code file; then implement the query function through the referenced encapsulation class "DBDA".

How to implement query function in php

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Code:


<body>
<h1>汽车信息</h1>
<?php
require"DBDA.class1.php";//$type 代表SQL语句的类型,0代表增删改,1代表查询
$db = new DBDA();

//如果没有提交数据,显示所有
//如果有提交数据,根据关键字查询显示
$name = "";
$tj1 = " 1=1 ";//第一个条件,对应名称,注意空格
$tj2 = " 1=1 ";//第二个条件,对应系列,注意空格
if(!empty($_POST["name"]))
{
  $name = $_POST["name"];
  $tj1 = " name like &#39;%{$name}%&#39;";
}
if(!empty($_POST["brand"]))
{
  $brand = $_POST["brand"];
  $tj2 = " brand like &#39;%{$brand}%&#39;";
}
//总条件
$tj ="{$tj1} and {$tj2}";
$sql = "select * from car where ".$tj;//注意where后空格
/*echo $sql;*/
?>
<form action="chaxun.php" method="post">
<p>名称:<input type="text" name="name" value="<?php echo $name ?>"/>系列:<input type="text" name="brand"/><input type="submit" value="查询" /></p>
</form>
<br/>
<table width="100%" border="1" cellpadding="0" cellspacing="0">
  <tr>
    <td>代号</td>
    <td>名称</td>
    <td>系列</td>
    <td>上市时间</td>
    <td>价格</td>
  </tr>
<?php

//只适用于单条件查询
/*$sql = "select * from car";
$name="";
if(!empty($_POST["name"]))
{
  $name = $_POST["name"];
  $sql = "select * from car where name like &#39;%{$name}%&#39; ";
}*/

$arr = $db->query($sql);
foreach($arr as $v)
  {
    $str = str_replace($name,"<span style=&#39;color:red&#39;>{$name}</span>",$v[1]);
    echo "<tr>
         <td>{$v[0]}</td>
        <td>{$str}</td>
        <td>{$v[2]}</td>
        <td>{$v[3]}</td>
        <td>{$v[7]}</td>
       </tr>";
  }
?>
</table>
</body>
</html>
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cited Encapsulation class


<?php
class DBDA
{
  public $host = "localhost";
  public $uid = "root";
  public $pwd = "123";
  public $dbname = "newssystem";
  //执行SQL语句返回相应的结果
  //$sql 要执行的SQL语句
  //$type 代表SQL语句的类型,0代表增删改,1代表查询
  function query($sql,$type=1)
  {
    $db = new MySQLi($this->host,$this->uid,$this->pwd,$this->dbname);
    
    $result = $db->query($sql);
    
    if($type)
    {
      //如果是查询,显示数据
      return $result->fetch_all();
    }
    else
    {
      //如果是增删改,返回true或者false
      return $result;
    }
  }
}
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