You can use the hashMap method to achieve this. The steps are as follows:
(Video tutorial recommendation: java course)
1 , The key in the HashMap stores the number of the array array, and the value stores the number of values in the array;
2. Traverse the HashMap, find the key whose Value value is equal to 1, and store it in the new array temp ;
3. Assign the values in the array temp to num1, num2;
The code is as follows:
import java.util.Map;
import java.util.HashMap;
import java.util.Set;
public class Solution {
public void FindNumsAppearOnce(int [] array,int num1[] , int num2[]) {
Map<Integer,Integer> map=new HashMap();
for(int i=0;i<array.length;i++){
if(map.containsKey(array[i])){
int len=map.get(array[i]);
map.put(array[i],len+1);
}else{
map.put(array[i],1);
}
}
int[] temp=new int[2];
int index=0;
Set<Map.Entry<Integer, Integer>> sm=map.entrySet();
for (Map.Entry<Integer, Integer> entry : sm) {
int t1=entry.getKey();
int t2=entry.getValue();
if(t2==1){
temp[index++] = t1;
}
}
num1[0]=temp[0];
num2[0]=temp[1];
}
}For more tutorials, please visit java Getting Started Tutorial column.
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