How does golang handle input?

Golang's method of processing input: 1. [fmt.Scan] interactively accepts input and uses spaces to segment words; 2. [fmt.Scanln] specifies the variable name and number of variables to receive input; 3. [fmt .Scanf] You need to specify the input format and directly filter out the unnecessary parts.

Golang’s method of processing input:

1. fmt.Scan

fmt.ScanInteractively accepts input and uses spaces to segment words. When calling the Scan function, you must specify the variable name and number of variables to receive input.

The Scan function will not return until all the specified variables are received, and the carriage return character cannot make it return in advance.

fmt.Println("Please enter the firstName and secondName: ")
fmt.Scan(&afirstName, &asecondName)
fmt.Printf("firstName is %s, secondName is %s\n", afirstName, asecondName)

The results are as follows:

Please enter the firstName and secondName:
zz
rr
firstName is zz, secondName is rr

2. fmt.Scanln

##ScanlnWhen calling, you must also specify the input to be received. Variable name and variable number.

\ n will cause the function to return early and assign variables that have not yet received values ​​when returning to empty.

fmt.Println("Please enter the firstName and secondName: ")
fmt.Scanln(&bfirstName, &bsecondName)
fmt.Printf("firstName is %s, secondName is %s\n", bfirstName, bsecondName)

Please enter the firstName and secondName:
zr
firstName is zr, secondName is

3. fmt.Scanf

Scanf to process input is more flexible. kind of processing method.

fmt.Println("Please enter the firstName and secondName: ")
fmt.Scanf("//%s\n%s", &cfirstName, &csecondName)
fmt.Printf("firstName is %s, secondName is %s", cfirstName, csecondName)

Please enter the firstName and secondName:
//zz
rr
firstName is zz, secondName is rr

Please enter the firstName and secondName:
//zr ui
firstName is zr, secondName is

Related learning recommendations:

Go language tutorial

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