How to solve the problem of CentOS firewall opening failure-CentOS-php.cn

How to solve the problem of CentOS firewall opening failure

angryTom

Release： 2020-03-17 18:17:57

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How to solve the problem of CentOS firewall opening failure

How to solve the problem of CentOS firewall startup failure

Suddenly I found that the centos 7 firewall could not be started, and the firewall-cmd command reported an error, the firewall The startup error is as follows:

[root@localhost firewalld]# systemctl start firewalld.service
Job for firewalld.service failed because the control process exited with error code. See "systemctl status firewalld.service" and "journalctl -xe" for details.
[root@localhost firewalld]# systemctl status firewalld.service
● firewalld.service - firewalld - dynamic firewall daemon
   Loaded: loaded (/usr/lib/systemd/system/firewalld.service; enabled; vendor preset: enabled)
   Active: failed (Result: exit-code) since 三 2020-01-08 10:43:48 CST; 10s ago
     Docs: man:firewalld(1)
  Process: 29630 ExecStart=/usr/sbin/firewalld --nofork --nopid $FIREWALLD_ARGS (code=exited, status=127)
 Main PID: 29630 (code=exited, status=127)

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The firewall-cmd command runs the error as follows: (Recommended learning: Linux video tutorial)

[root@localhost yangl]# firewall-cmd 
Traceback (most recent call last):
  File "/usr/bin/firewall-cmd", line 24, in 
    from gi.repository import GObject
ImportError: No module named gi.repository

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The reason is due to the use of Customize the installed python and use your own installed python as the default python (in addition, upgrading the system default python to python3 may also cause similar problems), so justreplace firewalld and firewall-cmd Changing the python called in the first line to the system python can be solved.

My python linking method is as follows:

[root@localhost yangl]# cd /usr/bin/
[root@localhost bin]# ll python*
lrwxrwxrwx. 1 root root   16 9月  28 2018 python -> /usr/bin/python2
lrwxrwxrwx. 1 root root   39 9月  28 2018 python2 -> /share/soft/python-2.7.15/bin/python2.7
-rwxr-xr-x. 1 root root 7216 7月  13 2018 python2.7      ＃系统的python
lrwxrwxrwx. 1 root root    9 9月  28 2018 python2_old -> python2.7
lrwxrwxrwx. 1 root root   36 3月   7 2018 python3 -> /share/soft/python-3.6.4/bin/python3
lrwxrwxrwx. 1 root root    7 9月  28 2018 python_old -> python2

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So, just vi open /usr/sbin/firewalld and /usr/bin/firewall-cmd, and change the first line by # !/usr/bin/python -Es can be changed to #!/usr/bin/python2.7 -Es!

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