When we query a certain field, sometimes we only want to match a certain piece of data. For example, if we want to query all the keywords of this article to see if a certain keyword exists, we often need to Matching, let's explain how to match and query a certain keyword value
The syntax of SQL fuzzy query is
"SELECT column FROM table WHERE column LIKE ';pattern';".
SQL provides four matching modes:
1. % represents any 0 or more characters. The following statement:
SELECT * FROM user WHERE name LIKE ';%三%';
will change the name to "Zhang San", "Three-legged Cat", "Tang Sanzang", etc. Find all characters with "three";
2. _ represents any single character. Statement:
SELECT * FROM user WHERE name LIKE ';_三_';
Only find "Tang Sanzang" whose name has three characters and the middle character is "三" ;
SELECT * FROM user WHERE name LIKE ';三__';
Only find "three-legged cat" whose name has three characters and the first character is "三" ;
3. [ ] represents one of the characters listed in brackets (similar to a regular expression). Statement:
SELECT * FROM user WHERE name LIKE ';[张李王]三';
will find "Zhang San", "Li San", "Wang San" (and Not "Zhang Li Wang San");
If [ ] contains a series of characters (01234, abcde, etc.), it can be abbreviated as "0-4", "a-e"
SELECT * FROM user WHERE name LIKE ';老[1-9]';
will find "old 1", "old 2",..., "old 9";
If you want to find the "-" character, please put it first: ';Zhang San[-1-9]';
4. [^ ] means a single character not listed in brackets. Statement:
SELECT * FROM user WHERE name LIKE ';[^Zhang Liwang]三';
will find "" whose surname is not "Zhang", "Li", or "Wang" Zhao San", "Sun San", etc.;
SELECT * FROM user WHERE name LIKE ';老[^1-4]';
will exclude "老1" to "老4 "Look for "Old 5", "Old 6",..., "Old 9".
! The last thing is the point!
Due to wildcards, our query statements for special characters "%", "_", "[", and "';" cannot be implemented normally, and it is convenient to enclose special characters with "[ ]" Can be queried normally. Based on this, we write the following function:
function sqlencode(str)
str=replace(str,"';","';';")
str =replace(str,"[","[[]") ';This sentence must come first
str=replace(str,"_","[_]")
str=replace(str,"%","[%]")
sqlencode=str
end function
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