How to get the first few digits of a string in java

Java method of intercepting the first digits of a string:

Recommendation: java video tutorial

1. Through subString( ) method to perform string interception.

subString provides different interception methods through different parameters

Pass in 2 index values

String sb = "bbbdsajjds";
sb.substring(0, 4);

Start from index number 0 and end at index 4 (and do not include Index 4 interception is included, which means that the actual interception is characters 0 to 3);

The running results are as follows:

bbbd

2. Through the method provided by StringUtils

StringUtils.substringBefore(“dskeabcee”, “e”);

/The result is: dsk/

Here, the first "e" is used as the standard.

StringUtils.substringBeforeLast(“dskeabcee”, “e”)

The result is: dskeabce

The last "e" shall prevail here.

For more java knowledge, please pay attention to the java basic tutorial column.

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