How to call api interface in python

爱喝马黛茶的安东尼
Release: 2019-06-20 11:05:37
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How python calls the api interface:

Interface protocol: http, webservice, rpc, etc.

Request method: get, post method

Request parameter format:

a. Get requests are all through url?param=xxx¶m1=xxx

b. Common types of request parameters for post requests include: application/json, application/x-www-form-urlencoded, multipart/form-data, text/html, etc.

You also need to know the url of the interface, parameter type, data format of the returned result, and whether the interface has header, cookie and other information.

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How to call api interface in python

##get method

# coding:utf-8 import json from urlparse import parse_qs from wsgiref.simple_server import make_server # 定义函数,参数是函数的两个参数,都是python本身定义的,默认就行了。 def application(environ, start_response): # 定义文件请求的类型和当前请求成功的code start_response('200 OK', [('Content-Type', 'text/html')]) # environ是当前请求的所有数据,包括Header和URL,body,这里只涉及到get # 获取当前get请求的所有数据,返回是string类型 params = parse_qs(environ['QUERY_STRING']) # 获取get中key为name的值 name = params.get('name', [''])[0] no = params.get('no', [''])[0] # 组成一个数组,数组中只有一个字典 dic = {'name': name, 'no': no} return [json.dumps(dic)] if __name__ == "__main__": port = 5088 httpd = make_server("0.0.0.0", port, application) print "serving http on port {0}...".format(str(port)) httpd.serve_forever()
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Request instance

How to call api interface in python

post method

# coding:utf-8 import json from wsgiref.simple_server import make_server # 定义函数,参数是函数的两个参数,都是python本身定义的,默认就行了。 def application(environ, start_response): # 定义文件请求的类型和当前请求成功的code start_response('200 OK', [('Content-Type', 'application/json')]) # environ是当前请求的所有数据,包括Header和URL,body request_body = environ["wsgi.input"].read(int(environ.get("CONTENT_LENGTH", 0))) request_body = json.loads(request_body) name = request_body["name"] no = request_body["no"] # input your method here # for instance: # 增删改查 dic = {'myNameIs': name, 'myNoIs': no} return [json.dumps(dic)] if __name__ == "__main__": port = 6088 httpd = make_server("0.0.0.0", port, application) print "serving http on port {0}...".format(str(port)) httpd.serve_forever()
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Request instance

How to call api interface in python

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