Why the expression 'in [1,0] == True' evaluates to false

The reason why the execution result of the expression "in [1,0] == True" is false: [==] in the expression is equivalent to and, that is, [(1 in [1, 0]) and ([1, 0] == True)].

Why is the execution result of in [1,0] == True false?

Running in python found:

>>> 1 in [1,0] == True     # This is strangeFalse
>>> False

Python actually applies comparison operator chaining here. The expression is translated to

(1 in [1, 0]) and ([1, 0] == True)

which is obviously False.

This also works for expressions like

a < b < c

converts to

(a < b) and (b < c)

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