Ajax check whether duplicate implementation code-JS Tutorial-php.cn

This article mainly introduces the implementation code of Ajax verification for duplication. It is very good and has reference value. Friends in need can refer to

and post the code directly!

1. Controller layer:

@ResponseBody @RequestMapping("entityFindByCode") public String entityFindByCode(Entity bean, HttpSession httpSession, Model m,HttpServletResponse res) throws IOException{ res.setContentType("text/plain; charset=UTF-8"); //res.reset(); //PrintWriter out = res.getWriter(); String data=null; @SuppressWarnings("unchecked") List list = (List) this.service.find("beanByCode", "Entity", new Object[]{bean.getCode()}); if(list.size()==0){ data="YES"; }else{ data="NO"; } res.getOutputStream().write(data.getBytes()); //out.print(data); //out.flush(); //out.close(); return data; }

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2. HTML layer:

$.ajax({ url :'entityFindByCode', type :'post', dataType :'text', data :{code:$("#code").val()},//{key,value} success :function(data) { if (data == "YES"){ document.getElementById("msg-code").innerHTML = "()"; return true; } else { $("#p-code").addClass("has-error"); document.getElementsByName("code")[0].value = ""; //document.getElementsByName("code")[0].setAttribute("placeholder", ""); document.getElementById("msg-code").innerHTML = "( !!!)"; return false; } } });

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The above is what I compiled for everyone. I hope it will be helpful to everyone in the future.

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