Detailed introduction to JS traversing the DOM tree-JS Tutorial-php.cn

Detailed introduction to JS traversing the DOM tree

php中世界最好的语言

Release： 2018-04-20 13:34:39

Original

3768 people have browsed it

This time I will bring you a detailed introduction to traversing the DOM tree with JS. What are the precautions when using JS to traverse the DOM tree? The following is a practical case, let’s take a look.

1 Introduction

Traversing the document tree is achieved by using the parentNode attribute, firstChild attribute, lastChild attribute, previousSibling attribute and nextSibling attribute.

1, parentNodeAttribute

This attribute returns the parent node of the current node.

[pNode=]obj.parentNode

pNode: This parameter is used to store the parent node. If the parent node does not exist, "null" will be returned.

2, firstChildAttribute

This attribute returns the first child node of the current node.

[cNode=]obj.firstChild

cNode: This parameter is used to store the first child node. If it does not exist, "null" will be returned.

3, lastChildAttribute

This attribute returns the last child node of the current node.

[cNode=]obj.lastChild

cNode: This parameter is used to store the last child node. If it does not exist, "null" will be returned.

4, previousSiblingAttribute

This attribute returns the previous sibling node of the current node.

[sNode=]obj.previousSibling

sNode: This parameter is used to store the previous sibling node. If it does not exist, "null" will be returned.

5, nextSiblingAttribute

This attribute returns the next sibling node of the current node.

[sNode=]obj.nextSibling

sNode: This parameter is used to store the next sibling node. If it does not exist, "null" will be returned.

Second application

Traverse the document tree. On the page, you can find the name, type and number of each node of the document through the corresponding button. node value.

Three codes

<head>
<title>遍历文档树</title>
</head>
<body >
<h3 id="h1">三号标题</h3>
<b>加粗内容</b>
<form name="frm" action="#" method="get">
节点名称：<input type="text" id="na"/><br />
节点类型：<input type="text" id="ty"/><br />
节点的值：<input type="text" id="va"/><br />
<input type="button" value="父节点" onclick="txt=nodeS(txt,&#39;parent&#39;);"/>
<input type="button" value="第一个子节点" onclick="txt=nodeS(txt,&#39;firstChild&#39;);"/>
<input type="button" value="最后一个子节点" onclick="txt=nodeS(txt,&#39;lastChild&#39;);"/><br>
<input name="button" type="button" onclick="txt=nodeS(txt,&#39;previousSibling&#39;);" value="前一个兄弟节点"/>
<input type="button" value="最后一个兄弟节点" onclick="txt=nodeS(txt,&#39;nextSibling&#39;);"/>
<input type="button" value="返回根节点" onclick="txt=document.documentElement;txtUpdate(txt);"/>
</form>
<script language="javascript">
<!--
function txtUpdate(txt)
{
 window.document.frm.na.value=txt.nodeName;
 window.document.frm.ty.value=txt.nodeType;
 window.document.frm.va.value=txt.nodeValue;
}
function nodeS(txt,nodeName)
{
switch(nodeName)
{
case"previousSibling":
if(txt.previousSibling)
{
 txt=txt.previousSibling;
}
else
 alert("无兄弟节点");
break;
case"nextSibling":
if(txt.nextSibling)
{
 txt=txt.nextSibling;
}
else
 alert("无兄弟节点");
break;
case"parent":
if(txt.parentNode)
{
 txt=txt.parentNode;
}
else
 alert("无父节点");
break;
case"firstChild":
if(txt.hasChildNodes())
{
 txt=txt.firstChild;
}
else
 alert("无子节点");
break;
case"lastChild":
if(txt.hasChildNodes())
{
 txt=txt.lastChild;
}
else
 alert("无子节点")
break;
}
 txtUpdate(txt);
return txt;
}
var txt=document.documentElement;
 txtUpdate(txt);
-->
</script>
</body>

Copy after login

Four running results

I believe you have mastered the method after reading the case in this article. For more exciting information, please pay attention to other related articles on the php Chinese website!