How to submit data in JSON format to the server-JS Tutorial-php.cn

This time I bring to you, what are theprecautionswhen submitting JSON format data to the server. The following is a practical case, let's take a look.

Prepare Hero.java

public class Hero { private String name; private int hp; public String getName() { return name; } public void setName(String name) { this.name = name; } public int getHp() { return hp; } public void setHp(int hp) { this.hp = hp; } @Override public String toString() { return "Hero [name=" + name + ", hp=" + hp + "]"; } } public class Hero { private String name; private int hp; public String getName() { return name; } public void setName(String name) { this.name = name; } public int getHp() { return hp; } public void setHp(int hp) { this.hp = hp; } @Override public String toString() { return "Hero [name=" + name + ", hp=" + hp + "]"; } }submit.html文件 [html] view plain copy print?    用AJAX以JSON方式提交数据  
   名称：
 血量：
  
 
         用AJAX以JSON方式提交数据  
   名称：
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The function of JSON.stringify function is to convert ajavascript objectinto astringin JSON format.

Prepare SubmitServlet to receive data

import java.io.IOException; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import net.sf.json.JSONObject; public class SubmitServlet extends HttpServlet { protected void service(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { String data =request.getParameter("data"); System.out.println("服务端接收到的数据是：" +data); JSONObject json=JSONObject.fromObject(data); System.out.println("转换为JSON对象之后是："+ json); Hero hero = (Hero)JSONObject.toBean(json,Hero.class); System.out.println("转换为Hero对象之后是："+hero); } } import java.io.IOException; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import net.sf.json.JSONObject; public class SubmitServlet extends HttpServlet { protected void service(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { String data =request.getParameter("data"); System.out.println("服务端接收到的数据是：" +data); JSONObject json=JSONObject.fromObject(data); System.out.println("转换为JSON对象之后是："+ json); Hero hero = (Hero)JSONObject.toBean(json,Hero.class); System.out.println("转换为Hero对象之后是："+hero); } }

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1. Get the string submitted by the browser

2. Convert the string into a JSON object

3 . Convert JSON object to Hero object

Finally configure web.xml

   SubmitServlet SubmitServlet   SubmitServlet /submitServlet      SubmitServlet SubmitServlet   SubmitServlet /submitServlet

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Start tomcat to access http://127.0.0.1:8080/project name/submit .html

#See the data coming from the tomcat console

I believe you have mastered the method after reading the case in this article. For more exciting information, please pay attention to other related articles on the php Chinese website!