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Simple bubble and two-way bubble sort cases

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Release: 2018-03-08 13:44:38
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This time I will bring you a simple bubble and two-way bubble sort case. What are the precautions for using bubble sequence? , the following is a practical case, let’s take a look.

Bubble sorting example, two-way bubble sorting and a slightly improved visualization of two-way bubble sorting.

Bubble sorting example

var ls=[ 98,13,6,25,38,36,30,44,38,80,61,28,47,34,95,18,85,58,89,85,42,61,74,35,13,14,80,7,10,44,10,47,13,11,52,25,24,48,34,12,88,80,33,8,80,45,64,52,79,77 ];
 
for(var i=0;i<ls.length;i++){
            for(var j=i+1;j<ls.length;j++){
                if(ls[i]>ls[j]){
                    ls[i]=ls[i]+ls[j];
                    ls[j]=ls[i]-ls[j];
                    ls[i]=ls[i]-ls[j];
                }
            }
        }
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Two-way bubble sorting example

var ls=[ 6,13,98,25,38,36,30,44,38,80,61,28,47,34,95,18,85,58,89,85,42,61,74,35,13,14,80,7,10,44,10,47,13,11,52,25,24,48,34,12,88,80,33,8,80,45,64,52,79,77 ];
 
for(var i=0;i<ls.length;i++){
            for(var j=i+1;j<ls.length-i;j++){
                if(ls[lent-1-i]<ls[lent-j]){
                    ls[lent-1-i]=ls[lent-1-i]+ls[lent-j];
                    ls[lent-j]=ls[lent-1-i]-ls[lent-j];
                    ls[lent-1-i]=ls[lent-1-i]-ls[lent-j];
                }//后面的比较
                if(ls[i]>ls[j]){
                    ls[i]=ls[i]+ls[j];
                    ls[j]=ls[i]-ls[j];
                    ls[i]=ls[i]-ls[j];
                }//前面的比较
            }
        }
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Two-way bubble sorting slightly improved example

var ls=[ 98,13,6,25,38,36,30,44,38,80,61,28,47,34,95,18,85,58,89,85,42,61,74,35,13,14,80,7,10,44,10,47,13,11,52,25,24,48,34,12,88,80,33,8,80,45,64,52,79,77 ];
 
var lent=ls.length;
for(var i=0;i<ls.length;i++){
            for(var j=i*2;j<ls.length-2*i;j++){
                if(ls[i*2]>ls[j+1]){
                    ls[i*2]=ls[i*2]+ls[j+1];
                    ls[j+1]=ls[i*2]-ls[j+1];
                    ls[i*2]=ls[i*2]-ls[j+1];
                }//保持内层第一个数为循环最小
                 
                if(ls[lent-i*2-1]<ls[lent-j-1]){
                    ls[lent-i*2-1]=ls[lent-i*2-1]+ls[lent-j-1];
                    ls[lent-j-1]=ls[lent-i*2-1]-ls[lent-j-1];
                    ls[lent-i*2-1]=ls[lent-i*2-1]-ls[lent-j-1];
                }////保持内层倒数第一个数为循环最大
                     
                    if(ls[lent-2-i*2]<ls[lent-j-1]){
                        ls[lent-2-i*2]=ls[lent-2-i*2]+ls[lent-j-1];
                        ls[lent-j-1]=ls[lent-2-i*2]-ls[lent-j-1];
                        ls[lent-2-i*2]=ls[lent-2-i*2]-ls[lent-j-1];
                    }//倒数上一个
                     
                    if(ls[i*2+1]>ls[j+1]){
                        ls[i*2+1]=ls[i*2+1]+ls[j+1];
                        ls[j+1]=ls[i*2+1]-ls[j+1];
                        ls[i*2+1]=ls[i*2+1]-ls[j+1];
                    }//下一个
            }
}
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I believe you have read this article You have mastered the case method. For more exciting information, please pay attention to other related articles on the PHP Chinese website!

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