This article mainly introduces the summary of the collection framework for Java review. The editor thinks it is quite good. Now I will share it with you and give you a reference. Let’s follow the editor and take a look.
As the saying goes: review the past and learn the new. Think about the knowledge you have learned. Even if you have learned it well before, you will forget it if you don't use it for a long time. Therefore, I think it is very necessary to review the knowledge you have learned before. This document reviews the collection framework in Java basics.
Why is there a collection framework?
Usually we use arrays to store some basic data types, or reference data types, but the length of the array is fixed. When the added elements exceed the length of the array, the array needs to be restructured. Definition, it would be too troublesome to write a program, so for our convenience, Java provides a collection class that can store any object. The length can be changed. It increases with the increase of elements and decreases with the decrease of elements. reduce.
Arrays can store basic data types or reference data types. Basic data types store values, reference data types store addresses, and collections can only store reference data types (that is, Object), in fact, basic data types can also be stored in collections, but they will be automatically boxed and turned into objects when stored.
Having a set does not mean that we have to abandon the array. If the number of elements that need to be stored is fixed, we can use an array, and when the elements stored are not fixed, we use a set.
Types of collections
Collections are divided into single-column collections and double-column collections. The root interface of a single-column collection is Collection, and the root interface of a double-column combination is Map. Both collections have collection classes (HashMap and HashSet) based on hashing algorithms. Now we may have questions about whether a double-column collection is based on a single-column collection. Or are single-column collections based on double-column collections? Let’s look at the source code for adding elements to the collections HashMap and HashSet:
/*
*HashMap的put 方法
*/
public V put(K key, V value) {
return putVal(hash(key), key, value, false, true);
}
final V putVal(int hash, K key, V value, boolean onlyIfAbsent,
boolean evict) {
Node<K,V>[] tab; Node<K,V> p; int n, i;
if ((tab = table) == null || (n = tab.length) == 0)
n = (tab = resize()).length;
if ((p = tab[i = (n - 1) & hash]) == null)
tab[i] = newNode(hash, key, value, null);
else {
Node<K,V> e; K k;
if (p.hash == hash &&
((k = p.key) == key || (key != null && key.equals(k))))
e = p;
else if (p instanceof TreeNode)
e = ((TreeNode<K,V>)p).putTreeVal(this, tab, hash, key, value);
else {
for (int binCount = 0; ; ++binCount) {
if ((e = p.next) == null) {
p.next = newNode(hash, key, value, null);
if (binCount >= TREEIFY_THRESHOLD - 1) // -1 for 1st
treeifyBin(tab, hash);
break;
}
if (e.hash == hash &&
((k = e.key) == key || (key != null && key.equals(k))))
break;
p = e;
}
}
if (e != null) { // existing mapping for key
V oldValue = e.value;
if (!onlyIfAbsent || oldValue == null)
e.value = value;
afterNodeAccess(e);
return oldValue;
}
}
++modCount;
if (++size > threshold)
resize();
afterNodeInsertion(evict);
return null;
}
/*
* HashSet 的add 方法
*/
public boolean add(E e) {
return map.put(e, PRESENT)==null;
}
// PRESENT是一个Object 对象
private static final Object PRESENT = new Object(); From the above source code, we can see , the add method does not appear in the source code of the put method of the double-column collection, and the add source code of the single-column collection can only blame the appearance of put; we can know that the single-column collection is implemented based on the double-column collection. In fact, the reason is very simple. Every time you add an element to a single-column collection, you only need to add a key. The key is also the unique identifier of the element in the double-column collection, and its value is replaced and hidden by an Object object. Every time you add it, the output element is Hiding the value of a single-column combination is based on a double-column set. Hiding one column is easy to implement. However, if it is a single-column set, it will be very difficult to turn it into a double-column set. It is like a magician performing magic tricks. Before changing something, you must prepare the thing you want to change in advance and just hide it. But if the magician really makes something from scratch, then I guess he is a god and can conjure whatever he wants.
Single-column collection
First we look at the inheritance diagram of single-column combination. The root interface of single-column collection is Collection, and The implementation classes of List are ArrayList, LinkedList, and Vector, and the implementation classes of Set interface are HashSet and TreeSet.
Secondly, let’s take a look at the functions of each collection
Overview of the unique functions of the List collection
* void add(int index,E element) //Add an element to the collection
* E remove(int index) //Delete the element at the index position in the collection
* E get(int index) //Get The element at the index position in the collection
* E set(int index,E element) Replace the element at the index position with element
Special functions of the Vector class
* public void addElement(E obj) Add element
* public E elementAt(int index) //Get element
* public Enumeration elements() //Get the enumeration of elements (used when iterating through iteration)
Special functions of the LinkedList class
* public void addFirst(E e) and addLast(E e) //Add elements to the head of the collection or add elements to the end of the collection
* public E getFirst() and getLast() //Get the head element and get the tail element
* public E removeFirst() and public E removeLast() //Delete the head element and delete the tail element
* public E get(int index);//Get index element
According to the above function of LinkedList, we can simulate the stack to obtain the data structure of the queue. The stack is first in, last out, and the queue is first in, first out.
/**
* 模拟的栈对象
* @author 毛麒添
* 底层还是使用LinkedList实现
* 如果实现队列只需要将出栈变为 removeFirst
*/
public class Stack {
private LinkedList linklist=new LinkedList();
/**
* 进栈的方法
* @param obj
*/
public void in(Object obj){
linklist.addLast(obj);
}
/**
* 出栈
*/
public Object out(){
return linklist.removeLast();
}
/**
* 栈是否为空
* @return
*/
public boolean isEmpty(){
return linklist.isEmpty();
}
}
//集合的三种迭代（遍历集合）删除
ArrayList<String> list=new ArrayList();
list.add("a");
list.add("b");
list.add("c");
list.add("world");
//1，普通for循环删除元素
for(int i=0;i<list,size();i++){//删除元素b
if("b".equals(list.get(i))){
list.remove(i--);// i-- 当集合中有重复元素的时候保证要删除的重复元素被删除
}
}
//2.使用迭代器遍历集合
Iterator<String> it=list.iterator();
while(it.hasNext){
if("b".equals(it.next())){
it.remove();//这里必须使用迭代器的删除方法，而不能使用集合的删除方法，否则会出现并发修改异常（ConcurrentModificationException）
}
}
//使用增强for循环来进行删除
for (String str:list){
if("b".equals(str)){
list.remove("b");//增强for循环底层依赖的是迭代器，而这里删除使用的依旧是集合的删除方法，同理肯定是会出现并发修改异常（ConcurrentModificationException），所以增强for循环一直能用来遍历集合，不能对集合的元素进行删除。
}
}接下里我们看Set集合，我们知道Set 集合存储无序，无索引，不可以存储重复的对象；我们使用Set集合都是需要去掉重复元素的, 如果在存储的时候逐个equals()比较, 效率较低,哈希算法提高了去重复的效率, 降低了使用equals()方法的次数，其中HashSet底层基于哈希算法，当HashSet调用add方法存储对象，先调用对象的hashCode()方法得到一个哈希值, 然后在集合中查找是否有哈希值相同的对象，如果没有哈希值相同的对象就直接存入集合，如果有哈希值相同的对象, 就和哈希值相同的对象逐个进行equals()比较,比较结果为false就存入, true则不存。下面给出HashSet存储自定义对象的一个例子，自定义对象需要重写hashCode()和equals()方法。
/**
* 自定义对象
* @author 毛麒添
* HashSet 使用的bean 重写了equals和HashCode方法
*/
public class Person1 {
private String name;
private int age;
public Person1() {
super();
// TODO Auto-generated constructor stub
}
public Person1(String name, int age) {
super();
this.name = name;
this.age = age;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
@Override
public String toString() {
return "Person1 [name=" + name + ", age=" + age + "]";
}
//使HashSet存储元素唯一
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + age;
result = prime * result + ((name == null) ? 0 : name.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
System.out.println("equals调用了");
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
Person1 other = (Person1) obj;
if (age != other.age)
return false;
if (name == null) {
if (other.name != null)
return false;
} else if (!name.equals(other.name))
return false;
return true;
}
}
public class Demo1_Hashset {
public static void main(String[] args) {
HashSet<Person1> hs=new HashSet<Person1>();
hs.add(new Person1("张三", 23));
hs.add(new Person1("张三", 23));
hs.add(new Person1("李四", 24));
hs.add(new Person1("李四", 24));
hs.add(new Person1("李四", 24));
hs.add(new Person1("李四", 24));
System.out.println(hs);
}运行结果如图，达到了不存储重复自定义对象的目的。其实HashSet的下面还有一个LinkedHashSet,底层是链表实现的，是set中唯一一个能保证怎么存就怎么取的集合对象,是HashSet的子类，保证元素唯一，与HashSet原理一样,这里就不多说了。
最后是TreeSet集合，该集合是用来进行排序的，同样也可以保证元素的唯一，可以指定一个顺序, 对象存入之后会按照指定的顺序排列。
指定排序有两种实现：
Comparable：集合加入自定义对象的时候，自定义对象需要实现Comparable接口，
实现接口的抽象方法中返回0，则集合中只有一个元素
返回正数，则集合中怎么存则怎么取，
返回负数，集合倒序存储
Comparator（比较器）：
创建TreeSet的时候可以制定 一个Comparator
如果传入了Comparator的子类对象, 那么TreeSet就会按照比较器中的顺序排序
add()方法内部会自动调用Comparator接口中compare()方法排序
调用的对象是compare方法的第一个参数,集合中的对象是compare方法的第二个参数
原理：
TreeSet底层二叉排序树
返回小的数字存储在树的左边（负数），大的存储在右边（正数），相等则不存（等于0）
在TreeSet集合中如何存取元素取决于compareTo（）方法的返回值
下面来看例子：
/**
* 自定义对象 用于TreeSet
* @author 毛麒添
*
*/
public class Person implements Comparable<Person>{
private String name;
private int age;
public Person(){
super();
}
public Person(String name, int age) {
super();
this.name = name;
this.age = age;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
@Override
public String toString() {
return "Person [name=" + name + ", age=" + age + "]";
}
@Override
public boolean equals(Object obj) {
Person p=(Person) obj;
return this.name.equals(p.name)&&this.age==p.age;
}
@Override
public int hashCode() {
// TODO Auto-generated method stub
return 1;
}
/*//按照年龄进行排序（TreeSet）
@Override
public int compareTo(Person o) {
int number=this.age-o.age;//年龄是比较的主要条件
//当年龄一样的时候比较名字来确定排序
return number==0?this.name.compareTo(o.name):number;
}*/
//按照姓名进行排序（TreeSet）
@Override
public int compareTo(Person o) {
int number=this.name.compareTo(o.name);//姓名是比较的主要条件
//当姓名一样的时候比年龄来确定排序
return number==0?this.age- o.age:number;
}
//按照姓名长度进行排序（TreeSet）
/*@Override
public int compareTo(Person o) {
int length=this.name.length()-o.name.length();//姓名长度比较的次要条件
int number=length==0?this.name.compareTo(o.name):length;//姓名是比较的次要条件
//比年龄也是次要条件
return number==0?this.age- o.age:number;
}*/
}
/**
*
* @author 毛麒添
* TreeSet集合
* 集合加入自定义对象的时候，自定义对象需要实现Comparable接口，
* 实现接口的抽象方法中返回0，则集合中只有一个元素
* 返回正数，则集合中怎么存则怎么取，
* 返回负数，集合倒序存储
*
* 将字符按照长度来进行排序在TreeSet中,需要使用有比较的构造方法进行比较。
*/
public class Demo_TreeSet {
public static void main(String[] args) {
// TODO Auto-generated method stub
demo1();//整数存取排序
demo2();//自定义对象排序
//将字符按照长度来进行排序在TreeSet中
TreeSet<String> strLenset=new TreeSet<String>(new compareByLen());
strLenset.add("aaaaa");
strLenset.add("lol");
strLenset.add("wrc");
strLenset.add("wc");
strLenset.add("b");
strLenset.add("wnnnnnnnnnnn");
System.out.println(strLenset);
}
private static void demo2() {
TreeSet<Person> ptreeSet=new TreeSet<Person>();
ptreeSet.add(new Person("李四",12));
ptreeSet.add(new Person("李四",16));
ptreeSet.add(new Person("李青",16));
ptreeSet.add(new Person("王五",19));
ptreeSet.add(new Person("赵六",22));
System.out.println(ptreeSet);
}
private static void demo1() {
TreeSet< Integer> treeSet=new TreeSet<Integer>();
treeSet.add(1);
treeSet.add(1);
treeSet.add(1);
treeSet.add(3);
treeSet.add(3);
treeSet.add(3);
treeSet.add(2);
treeSet.add(2);
treeSet.add(2);
System.out.println(treeSet);
}
}
//TreeSet 构造器，实现compare对需要存储的字符串进行比较
class compareByLen implements Comparator<String>{
//按照字符串的长度进行比较，该方法的返回值和继承Comparable的compareTo方法返回值同理。
@Override
public int compare(String o1, String o2) {
int num=o1.length()-o2.length();//以长度为主要条件
return num==0?o1.compareTo(o2):num;//内容为次要条件
}
}下面是运行截图，其中compareTo的实现方法对几种条件排序进行了实现，具体可以查看Person自定义类中的实现。
单列集合复习就到这里吧。
双列集合
同样的，在复习双列结合之前我们先看看双列集合的继承图。
Map集合的功能梳理：
添加功能
V put(K key,V value):添加元素。
如果键是第一次存储，就直接存储元素，返回null
如果键不是第一次存在，就用值把以前的值替换掉，返回以前的值
删除功能
void clear():移除所有的键值对元素
V remove(Object key)：根据键删除键值对元素，并把值返回
判断功能
boolean containsKey(Object key)：判断集合是否包含指定的键
boolean containsValue(Object value):判断集合是否包含指定的值
boolean isEmpty()：判断集合是否为空
获取功能
Set
V get(Object key):根据键获取值
Set
Collection
长度功能
int size()：返回集合中的键值对的个数
Map类集合也有三种遍历方式：
使用迭代器进行遍历
使用增强For循环来进行遍历
使用Map.Entry来遍历集合中的元素
下面我们来看看如何实现上面三种遍历方式
/**
*
* @author 毛麒添
* Map 集合的遍历
*/
public class Demo {
public static void main(String[] args) {
Map<String ,Integer> map=new HashMap<String, Integer>();
map.put("张三", 18);
map.put("李四", 19);
map.put("王五", 20);
map.put("赵六", 21);
//使用迭代器进行遍历
/*Set<String> keySet = map.keySet();//获取所有key的集合
Iterator<String> iterator = keySet.iterator();
while(iterator.hasNext()){
String key = iterator.next();
Integer i=map.get(key);
System.out.println(i);
}*/
//使用增强For循环来进行遍历
for (String key :map.keySet()) {
Integer integer = map.get(key);
System.out.println(integer);
}
/*---------------------------使用Map.Entry来遍历集合中的元素--------------------------*/
Set<Map.Entry<String,Integer>> en=map.entrySet();////获取所有的键值对象的集合
/*//使用迭代器来遍历
Iterator<Entry<String, Integer>> iterator = en.iterator();
while(iterator.hasNext()){
Entry<String, Integer> e=iterator.next();//获取键值对对象
String key = e.getKey();//根据键值对对象获取键
Integer value = e.getValue();//根据键值对对象获取值
System.out.print(key);
System.out.println(value);
}*/
//使用增强for循环来遍历
for (Entry<String, Integer> entry : en) {
String key = entry.getKey();
Integer value = entry.getValue();
System.out.print(key);
System.out.println(value);
}
/*---------------------------使用Map.Entry来遍历集合中的元素--------------------------*/
}
}LinkHashMap与LinkHashSet一样，怎么存怎么取，保证元素唯一（key 是唯一判定值）,由于保证元素唯一，其性能肯定会低一些，这里就不细说了。
TreeMap是双列集合，其实他和TreeSet是很像的，但是双列集合的键是唯一标识，所以TreeMap排序的是每个元素的键。对于存储自定义对象排序，它也有Comparable和Comparator，下面我们来看例子
/**
*
* @author 毛麒添
* TreeMap
* 通TreeSet 原理，存取自定义对象也需要继承Comparable结构，
* 或者实现比较器Comparator
*/
public class Demo6_TreeMap {
public static void main(String[] args) {
TreeMap<Student, String> tm=new TreeMap<Student, String>(new Comparator<Student>() {
@Override
public int compare(Student s1, Student s2) {
int num=s1.getName().compareTo(s2.getName());//以姓名作为主要比较条件
return num==0?s1.getAge()-s2.getAge():num;
}
});
tm.put(new Student("张三",13),"杭州");
tm.put(new Student("张三",14), "贺州");
tm.put(new Student("王五",15), "广州");
tm.put(new Student("赵六",16), "深圳");
System.out.println(tm);
}
}
/**
* 自定义对象
* @author 毛麒添
* HashMap 存储对象 与 HashSet 同理 需要重写 hashcode 和equals 方法
* TreeMap 实现 Comparable接口
*/
public class Student implements Comparable<Student>{
private int age;
private String name;
public Student(){
super();
}
public Student(String name,int age){
this.name=name;
this.age=age;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
@Override
public String toString() {
return "Student [age=" + age + ", name=" + name + "]";
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + age;
result = prime * result + ((name == null) ? 0 : name.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
Student other = (Student) obj;
if (age != other.age)
return false;
if (name == null) {
if (other.name != null)
return false;
} else if (!name.equals(other.name))
return false;
return true;
}
@Override
public int compareTo(Student o) {
int num =this.age-o.age;//以年龄为主要条件
return num==0?this.name.compareTo(o.name):num;//姓名作为次要条件
}
}到这里，Java集合框架的复习基本完成，最后来一个斗地主的例子对集合框架做一个综合应用，只是实现斗地主洗牌和发牌，至于怎么打牌，逻辑复杂，这里不做实现。
/**
*
* @author 毛麒添
* 模拟斗地主洗牌和发牌，牌排序
* 买一副扑克
* 洗牌
* 发牌
* 看牌
*/
public class Doudizhu_progress {
public static void main(String[] args) {
// TODO Auto-generated method stub
//构造一副扑克牌
String[] number={"3","4","5","6","7","8","9","10","J","Q","K","A","2"};
String[]color={"黑桃","红桃","梅花","方块"};
HashMap<Integer, String> pokerMap=new HashMap<Integer, String>();//存放牌的map
ArrayList<Integer> list=new ArrayList<Integer>();//存放牌的索引
int index=0; //索引
for (String s1 : number) {
for (String s2 : color) {
pokerMap.put(index,s2.concat(s1));
list.add(index);
index++;
}
}
//加入大小王
pokerMap.put(index,"小王");
list.add(index);
index++;
pokerMap.put(index,"大王");
list.add(index);
//洗牌
Collections.shuffle(list);
//System.out.println(list);
//发牌，3个人玩 加上底牌3张 使用TreeSet 来存放索引，并自动对索引排好序
TreeSet<Integer> mao=new TreeSet<Integer>();
TreeSet<Integer> li=new TreeSet<Integer>();
TreeSet<Integer> huang=new TreeSet<Integer>();
TreeSet<Integer> dipai=new TreeSet<Integer>();
for(int i=0;i<list.size();i++){
if(i>=list.size()-3){//最后三张牌，作为底牌
dipai.add(list.get(i));
}else if(i%3==0){
mao.add(list.get(i));
}else if(i%3==1){
li.add(list.get(i));
}else {
huang.add(list.get(i));
}
}
//看牌
lookPoker(pokerMap,mao,"mao");
lookPoker(pokerMap,li,"li");
lookPoker(pokerMap,huang,"huang");
lookPoker(pokerMap,dipai,"底牌");
}
/**
* 看牌的方法
* @param pokerMap 存放牌的map
* @param mao 该玩家的牌的索引集合
* @param name 玩家名字
*/
private static void lookPoker(HashMap<Integer, String> pokerMap,
TreeSet<Integer> mao, String name) {
if(name.equals("底牌")){
System.out.print("地主"+name+"的牌是：");
}else{
System.out.print("玩家"+name+"的牌是：");
}
for (Integer integer : mao) {
System.out.print(pokerMap.get(integer)+" ");
}
System.out.println();
}
}运行截图：
写在最后：
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