Home > Backend Development > PHP Tutorial > Analysis of path method for converting php array to string to obtain array representation

Analysis of path method for converting php array to string to obtain array representation

黄舟
Release: 2023-03-15 17:48:01
Original
1693 people have browsed it

This article mainly introduces the path for PHP to obtain array representation, and compares and analyzes the implementation techniques of converting arrays to strings in the form of examples. Friends in need can refer to the following

The examples in this article describe how PHP obtains array representation. path method. Share it with everyone for your reference. The details are as follows:

Problem:

During the file parsing process, it was found that a path is stored in the form of an array. Now it is necessary to store the complete path in characters String format output

Solution:


$hostspath=array('Windows','System32','drivers','etc','hosts');
$pathstr='';
foreach($hostspath as $k=>$v){
 $pathstr.=$v.'/';
}
$pathstr=substr($pathstr,0,-1);
echo $pathstr;
Copy after login

Output:


Windows/System32/drivers/etc/hosts
Copy after login
Copy after login

After writing the above code, I thought that this is a problem of converting an array to a string, and a simpler method can be used!

Improvement method:


##

$hostspath=array('Windows','System32','drivers','etc','hosts');
$pathstr=implode('/',$hostspath);
echo $pathstr;
Copy after login

The output result is also:


Windows/System32/drivers/etc/hosts
Copy after login
Copy after login

Summary:

Using PHP’s own system functions to solve problems is often simpler and more efficient than the algorithms you come up with yourself!

The above is the detailed content of Analysis of path method for converting php array to string to obtain array representation. For more information, please follow other related articles on the PHP Chinese website!

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template