Test question:

$(document).ready(function(){
    $("tr:gt(0):lt(2)").css("background-color","#B2E0FF");
});

If the positions of gt() and lt() are swapped, the displayed results will be different! ~
Putting lt() in front is the result I want, but putting gt() in front is a pitfall.
The following code comes from w3cshool. My project jquery1.8.2.js also has similar problems.
Looking forward to the master explaining the reason for this. .

   
  



Welcome to My Web Page
 


Id
LastName
 
FirstName
Address
City

 

1
Adams
John
Oxford Street
 
London

 

2
Bush
George
Fifth Avenue
New York 

 

3
Carter
Thomas
Changan Street
Beijing

 

4
Obama
Barack
Pennsylvania Avenue
Washington

 

 


 

:gt(n) All elements with serial numbers greater than n
:lt(n) All elements with serial numbers less than n
:gt(0):lt(2) Represents numbers 1 and 2 Element
:lt(2):gt(0) means element No. 1

Yes, :gt(0):lt(2) can be understood as 0< index <= 2, :lt (2): gt(0) is 0< index < 2; the jquery manual does not introduce this usage. Is this a bug?

a,b,c,d,e
:gt(0) gets
b,c,d,e
:lt(2) gets
b,c

The selector filters down step by step, and each step of filtering is performed on the results of the previous step

a,b,c,d,e
:gt(0) Get
b,c,d,e
:lt(2) gets
b,c

The selector is filtered step by step, and each step of filtering is based on the results of the previous step. ongoing

The above is the detailed content of Solve the problem of Jquery :lt(index) and :gt(index)) selectors. For more information, please follow other related articles on the PHP Chinese website!