func_num_args(): Returns the number of parameters passed in to the calling function, the type is integer.
This function can be used in conjunction with func_get_arg() and func_get_args() to allow user-defined functions to receive variable-length parameter lists.
Return value
Returns the number of parameters passed into the function defined by the current user.
Usage example:
function foo()
{
$numargs = func_num_args();//返回这个函数所含的参数
echo "Num fo argumets : $numargs <br>\n";
$arr=func_get_args();//返回一个数组给$arr
print_r($arr);//输出这个数组所有的参数
echo "<hr>";
for($i=0;$i<=$numargs;$i++)
{
echo $arr[$i]."<br>";
}
}
foo(1,2,3,45,6);The running results are as follows:
Num fo argumets : 5 Array ( [0] => 1 [1] => 2 [2] => 3 [3] => 45 [4] => 6 ) -------------------------------------------------------------------------------- 1 2 3 45 6
Example 2:
<?php
function foo() {
include './fna.php';
}
foo('First arg', 'Second arg');
?>
fna.php
<?php
$num_args = func_num_args();
var_export($num_args);
?>The above is the detailed content of PHP func_num_args() function introduction and usage examples. For more information, please follow other related articles on the PHP Chinese website!
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